我是python新手,但到目前为止我非常喜欢这种语言
我一直在创建一系列复杂的html5元素,并使用html5lib模块
当我浏览段落中的元素时,我可以很好地将它们打印出来,但当我尝试使用bs4的insert方法时,我只得到其他元素的输出,我不知道为什么
我的python:
i = 0
for gallery_elem in gallery_header_next_sibling:
if ( gallery_elem.name.lower() == 'img' ):
if ( i == 0 ):
new_gallery = soup.new_tag( "div" )
new_gallery[ "class" ] = "gallery"
new_gallery_elem = soup.new_tag( "figure" )
if ( gallery_elem.has_attr( "alt" ) ):
new_gallery_cap = soup.new_tag( "figcaption" )
new_gallery_cap.string = gallery_elem[ "alt" ]
new_gallery_elem.insert( 2, new_gallery_cap )
if ( gallery_elem.has_attr( "title" ) ):
new_gallery_attribution = soup.new_tag( "dl" )
new_gallery_attribution_dt = soup.new_tag( "dt" )
new_gallery_attribution_dt.string = "Image owner:"
new_gallery_attribution_dd = soup.new_tag( "dd" )
new_gallery_attribution_dd.string = gallery_elem[ "title" ]
new_gallery_attribution.insert( 0, new_gallery_attribution_dt )
new_gallery_attribution.insert( 1, new_gallery_attribution_dd )
new_gallery_elem.insert( 1, new_gallery_attribution )
new_gallery_elem.insert( 1, gallery_elem )
i = i + 1
new_gallery_elem.insert( 1, gallery_elem )
HTML
<img alt="Caption One." src="img/orange.jpg" title="Attribution One."/>
<img alt="Caption Two." src="img/red.jpg" title="Attribution Two."/>
<img alt="Caption Three." src="img/urban.jpg" title="Attribution Three."/>
<img alt="Caption Four." src="img/brolly.jpg" title="Attribution Four."/>
<img alt="Caption Five." src="img/tomy.jpg" title="Attribution Five."/>
输出:
<figure><figcaption>Caption One.</figcaption><img alt="Caption One." src="img/orange.jpg" title="Attribution One."/><dl><dt>Image owner:</dt><dd>Attribution One.</dd></dl></figure>
<figure><figcaption>Caption Three.</figcaption><img alt="Caption Three." src="img/urban.jpg" title="Attribution Three."/><dl><dt>Image owner:</dt><dd>Attribution Three.</dd></dl></figure>
<figure><figcaption>Caption Five.</figcaption><img alt="Caption Five." src="img/tomy.jpg" title="Attribution Five."/><dl><dt>Image owner:</dt><dd>Attribution Five.</dd></dl></figure>
如果我拔出下面的一行,我会得到所有的五个元素。有人知道我做错了什么吗
new_gallery_elem.insert( 1, gallery_elem )
因此,经过一些实验后,我发现如果我将所需的元素存储在一个列表中,然后从列表中检索它们,而不是试图编辑“现场汤”,那么问题就迎刃而解了
一旦创建并存储了这些对象,我就可以将它们添加回先前创建并插入到soup中的父元素中
我希望这能解决其他人过早脱发的问题
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