如何在不使用python中的多个if/else语句的情况下多次生成随机列表？

Question

我试图生成一个列表五次，只使用一个while循环和一个数字列表。我编写的代码对我来说似乎很好，但列表只生成一次，然后为其他测试生成相同的列表。每次我都要一张随机列表。我不知道出了什么问题，所以我不知道如何解决它。任何帮助都将不胜感激

这是我的密码：

import random, time

number = 23
counter = 0
total = 5
counter2 = 0
current = 0
numbers = []
tally = 1
trash = []

while counter < total:
  while counter2 < number:
    for x in range(1):
      current = random.randint(1, 366)
      time.sleep(0.0001)
      counter2 += 1
      numbers.append(current)
  numbersS = set(numbers)
  size = len(numbersS)
  if size < number:
    print("1")
  else:
    print("0")
  counter += 1
  numbers = trash

Answer 1

I do not know what is wrong

行numbers = trash不是您想要的。它不会清空列表，只会使numbers成为trash的同义词。这意味着下次执行numbers.append(current)时，您实际上会将该值添加到trash列表中

查看此简化代码和注释：

trash = []
numbers = []

numbers.append(1) # adds to numbers, not to trash

numbers = trash # now both names are synonyms for the same list; currently empty

numbers.append(2) # adds to trash(!)

numbers = trash # this was already the case: does not do anything

print(numbers, trash) # [2] [2]

你应该只做numbers = []而不是numbers = trash。或者，您可以使用相同的列表，并使用del numbers[:]或numbers.clear()将其截断