这是我从客户端接收数据的python脚本:
import time
import socket
HOST = ''
PORT = 8888
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print('Socket created')
try:
s.bind((HOST, PORT))
except socket.error as socketError:
print('socket binding failed, ', socketError)
print('Exiting...')
sys.exit(0)
print('Socket binding complete')
s.listen(1)
print('Socket listening for connection...')
conn, addr = s.accept()
print('connected to ', addr[0])
bfr = b''
try:
while True:
while True:
temp = conn.recv(1024)
print('temp is ',temp.decode('utf-8'))
print('buffer value ', bfr.decode('utf8'))
if not temp:
break
bfr += temp;
data = bfr.decode('utf-8')
bfr = b''
print('value received,', data)
if data == 'Connection-Ready to receive commands':
print('')
#other conditions
except Exception as loopException:
print("Exception occurred in loop, exiting...")
finally:
s.close()
脚本在打印后挂起
connected to 192.168.4.197
并且不接受来自客户端的任何命令。如果客户端断开连接,将打印所有发送命令
有人知道为什么会这样吗?请询问您是否需要更多详细信息
更新1
尝试删除内部while并添加了一个time.sleep(.10)
,脚本没有挂起,但只有第一个命令按原样打印,其余命令在第一个字符后使用换行符打印,例如,如果我发送10,它将先打印1,然后在另一行打印0。我只想在从客户端发送命令时获取命令,每个命令都是一个单词
也许可以尝试
sendall
以确保从客户端发送完整的数据相关问题 更多 >
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