显示前拒绝重置为零的分数

Question

我正在尝试用python创建一个骰子游戏，其中一个规则是当分数低于零时会重置

我曾尝试在开始、结束和掷骰子脚本中设置分数重置检查，但它们总是允许分数低于零

#import all modules.
import math
import random 
print("successfully imported modules.")
roundno=0
p1score=0
p2score=0
p1dicecomb=0
p2dicecomb=0
p1dice1=0
p1dice2=0
p2dice1=0
p2dice2=0 # assign values.
while roundno < 6:
    if p2score < -1 or p2score == -1:
        p2score = 0
    if p1score < -1 or p1score == -1:
        p1score = 0
    print("round number is round", roundno) #new round always begins on player 1 turn.
    print("player 1")
    p1dice1 = random.randint(1,6)
    p1dice2 = random.randint(1,6)# roll dice using cpu.
    p1dicecomb = p1dice1+p1dice2
    if p1dicecomb % 2 == 0:
        p1score = p1score+10# compare the score to see if odd or even.
    if p1dicecomb % 2 == 1:
        p1score = p1score-5
    print ("score is", p1score)
    print("dice 1 is", p1dice1)
    print("dice 2 is", p1dice2)
    input("press enter to continue rolling dice.")
    print ("player 2")
    if p2score < -1 or p2score == -1:
        p2score = 0
    if p1score < -1 or p1score == -1:
        p1score = 0
    p2dice1 = random.randint(1,6)
    p2dice2 = random.randint(1,6)# roll dice using cpu.
    p2dicecomb = p2dice1+p2dice2

    if p2dicecomb % 2 == 0:
        p2score = p2score+10# compare the score to see if odd or even.
    if p2dicecomb % 2 == 1:
        p2score = p2score-5
    print ("score is", p2score)
    print("dice 1 is", p2dice1)
    print("dice 2 is", p2dice2)
    roundno = roundno+1
    input("press enter to continue rolling dice.")

我希望当代码变为-5时，它应该将分数重置回零，但是它说分数是-5

Answer 1

设置分数后，您没有进行小于零的检查

为了测试，我添加了以下几行：

#Stuff before...
    p2dice1 = random.randint(1,6)
    p2dice2 = random.randint(1,6)# roll dice using cpu.
    p2dicecomb = p2dice1+p2dice2

    print(p2score)
    print(p2dicecomb)

    if p2dicecomb % 2 == 0:
        p2score = p2score+10# compare the score to see if odd or even.
    if p2dicecomb % 2 == 1:
        p2score = p2score-5
    print ("score is", p2score)

您将看到第一次打印p2score时，它是0。如果p2dicecomb是奇数，那么p2score变成0-5，即-5

稍微重新排列代码，在减法后设置检查，例如：

import math
import random 
print("successfully imported modules.")
roundno=0
p1score=0
p2score=0
p1dicecomb=0
p2dicecomb=0
p1dice1=0
p1dice2=0
p2dice1=0
p2dice2=0 # assign values.
while roundno < 6:
    if p2score < -1 or p2score == -1:
        p2score = 0
    if p1score < -1 or p1score == -1:
        p1score = 0
    print("round number is round", roundno) #new round always begins on player 1 turn.
    print("player 1")
    p1dice1 = random.randint(1,6)
    p1dice2 = random.randint(1,6)# roll dice using cpu.
    p1dicecomb = p1dice1+p1dice2
    if p1dicecomb % 2 == 0:
        p1score = p1score+10# compare the score to see if odd or even.
    if p1dicecomb % 2 == 1:
        p1score = p1score-5
    if p1score < -1 or p1score == -1:
        p1score = 0
    print ("score is", p1score)
    print("dice 1 is", p1dice1)
    print("dice 2 is", p1dice2)
    input("press enter to continue rolling dice.")
    print ("player 2")

    p2dice1 = random.randint(1,6)
    p2dice2 = random.randint(1,6)# roll dice using cpu.
    p2dicecomb = p2dice1+p2dice2

    if p2dicecomb % 2 == 0:
        p2score = p2score+10# compare the score to see if odd or even.
    if p2dicecomb % 2 == 1:
        p2score = p2score-5

    if p2score < -1 or p2score == -1:
        p2score = 0
    print ("score is", p2score)
    print("dice 1 is", p2dice1)
    print("dice 2 is", p2dice2)
    roundno = roundno+1
    input("press enter to continue rolling dice.")

（也可以导入math，但不要使用它！）

Answer 2

这是操作顺序的问题：

1. 如果分数为负值，则将其重置为0
2. 你掷骰子
3. 应用+10或-5操作
4. 打印结果，此时结果可能为负数

所以，如果打印的分数有时是负片，这是正常的

以下是一个工作示例：

import random 

roundno = 0
p1score, p2score = 0, 0
p1dice1, p1dice2 = 0, 0
p2dice1, p2dice2 = 0, 0

while roundno < 6:
    print("round number is round", roundno) #new round always begins on player 1 turn.

    print("player 1")
    p1dice1, p1dice2 = random.randint(1,6), random.randint(1,6) # roll dice using cpu.

    # compare the score to see if odd or even.
    if (p1dice1 + p1dice2) % 2 == 0:
        p1score += 10
    else:
        p1score -= 5

    if p1score < 0:
        p1score = 0

    print ("score is", p1score)
    print("dice 1 is", p1dice1)
    print("dice 2 is", p1dice2)

    input("press enter to continue rolling dice.")

    print ("player 2")

    # roll dice using cpu.
    p2dice1, p2dice2 = random.randint(1,6), random.randint(1,6)

    # compare the score to see if odd or even.
    if (p2dice1 + p2dice2) % 2 == 0:
        p2score += 10   
    else:
        p2score -= 5

    if p2score < 0:
        p2score = 0

    print ("score is", p2score)
    print("dice 1 is", p2dice1)
    print("dice 2 is", p2dice2)

    roundno = roundno+1
    input("press enter to continue rolling dice.")

Answer 3

重新阅读代码后，我发现代码不正确

正确的代码是：

    p1dicecomb = p1dice1+p1dice2
    if p1dicecomb % 2 == 0:
        p1score = p1dicecomb +10# compare the score to see if odd or even.
    if p1dicecomb % 2 == 1:
        p1score = p1dicecomb-5

这为我解决了问题