列出csv fi中的URL

Question

我试着列出csv文件中的url，看看它们的HTTP代码是什么。到目前为止我得到的是：

import urllib.request, urllib.error

url = ['http://www.10vibes.info'
       'http://www.10vibes.info']

try:
    conn = urllib.request.urlopen(url)
except urllib.error.HTTPError as e:
    print(e.code)
except urllib.error.URLError as e:
    print('URLError')
else:
    print('good')

Answer 1

以字符串形式传递url，如下所示：

import urllib.request, urllib.error

url = ['http://www.10vibes.info'
       'http://www.10vibes.info']

for my_url in url:
   try:
       conn = urllib.request.urlopen(my_url)
   except urllib.error.HTTPError as e:
       # Return code error (e.g. 404, 501, ...)
       # ...
       print(e.code)
       pass
   except urllib.error.URLError as e:
       # Not an HTTP-specific error (e.g. connection refused)
       # ...
       print('URLError')
       pass

   print('good')