如何从该模型中获取对象?

2024-04-25 01:19:10 发布

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我正在尝试创建一个地址模型/views/。。。这是可行的,我让模型工作,但我试图访问它包含的数据,它不工作。模型如下:

class Profile(models.Model):
    user = models.OneToOneField(User, on_delete=models.CASCADE)
    nick_name = models.CharField('Nick name', max_length=30, blank=True, default='')
    bio = models.TextField(max_length=500, blank=True)
    image = models.ImageField(default='default.jpg', upload_to='profile_pics')
    # Address = models.ForeignKey('Address', on_delete=models.CASCADE)

    # If we don't have this, it's going to say profile object only
    def __str__(self):
        return self.user.username
        #return f'{self.user.username}'  # it's going to print username Profile

    def save(self, *args, **kwargs):
            super().save(*args, **kwargs)

            img = Image.open(self.image.path)

            if img.height > 300 or img.width > 300:
                output_size = (300, 300)
                img.thumbnail(output_size)
                img.save(self.image.path)


class Address(models.Model):
    users = models.ManyToManyField(Profile, blank=True)
    name = models.CharField(max_length=30)
    address = models.CharField(max_length=50)
    city = models.CharField(max_length=60, default="Miami")
    state = models.CharField(max_length=30, default="Florida")
    zipcode = models.CharField(max_length=5, default="33165")
    country = models.CharField(max_length=50)

    class Meta:
        verbose_name_plural = 'Address'

    def __str__(self):
        return self.name

我正在尝试访问用户可以拥有的所有地址。我试过:

# TESTS
allAddresses = Address.objects.all()
print(allAddresses)

对于它给我的地址对象:<QuerySet [<Address: Elizabeth>, <Address: Work>]>

但如果我试着按用户过滤,像这样:

allAddresses = Address.objects.all().filter(users='arturo')
print(allAddresses)

它给我一个错误:invalid literal for int() with base 10: 'arturo'

有人能带我去获取登录用户的所有地址吗

非常感谢


Tags: name模型selfdefaultimgaddressmodels地址
1条回答
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1楼 · 发布于 2024-04-25 01:19:10

filter约束users引用中间多对多表的ID,因此出现错误。您应该指定完整的相关字段,其中user表示Profile.user字段,username表示User.username字段:

allAddresses = Address.objects.all().filter(users__user__username='arturo')

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