表中单词的标记化senten

Question

我有一个单词/用具的清单

appliances = ['tv', 'radio', 'oven', 'speaker']

我还有一个句子，我已经标记了

sent = ['We have a radio in the Kitchen']
sent1 = word_tokenize[sent]

我想说，如果电器是在sent1然后打印是，否则打印否。我做了下面的，但不断得到作为打印否

if any(appliances) in sent1:
    print ('yes')
else:
    print ('no')

有没有更好的办法

Answer 1

试试这样的

appliances = ['tv', 'radio', 'oven', 'speaker']
sent = ['We have a radio in the Kitchen']
sent1 = list(sent[0].split())

if any([app in sent1 for app in appliances]):
    print ('yes')
else:
    print ('no')

根据@tobias\u k评论编辑

使用惰性评估

if any(app in sent1 for app in appliances):
    print ('yes')
else:
    print ('no')

编辑：基于@ben121评论

如果你想看看你的句子里有没有电器，你可以这样做

[app for app in appliances if app in sent1]