日期为日期时间格式 周末需要有相同的数字,其余的按数字顺序向下移动。 df1型
Date Number
0. 12-10-2018 1
1. 13-10-2018 2
2. 14-10-2018 3
3. 15-10-2018 4
4. 16-10-2018 5
5. 17-10-2018 6
6. 18-10-2018 7
7. 18-10-2018 8
8. 19-10-2018 9
我的代码:
i = 1
df1['Number'][0] == 1
for i range(len(df1[0])):
if df1[0[i].weekday()== 4:
df1['Number'].iloc[i+1] = df1['Number'].iloc[i]
elif df1[0][i].weekday() == 5:
df1['Number'].iloc[i+1] = df1['Number'].iloc[i]
这将为我提供数字输出:
df1型
Date Number
0. 12-10-2018 1
1. 13-10-2018 1
2. 14-10-2018 1
3. 15-10-2018 4
4. 16-10-2018 5
5. 17-10-2018 6
6. 18-10-2018 7
7. 19-10-2018 8
8. 20-10-2018 8
我需要输出:
df1型
Date Number
0. 12-10-2018 1
1. 13-10-2018 1
2. 14-10-2018 1
3. 15-10-2018 2
4. 16-10-2018 3
5. 17-10-2018 4
6. 18-10-2018 5
7. 19-10-2018 6
8. 20-10-2018 6
非常感谢
我们可以通过
factorize
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