当我使用命令行参数时，为什么python将我的文件名作为一个值来计算？

Question

我已经试着修复它，并且已经检查了我的代码很多次，但是看起来没有什么问题

我已将模块解压为3个值并尝试运行程序，但它给了我一个错误，即我给出的值太多：

PS C:\dir1>；python exlp.py拉面清爽圆润

回溯（最近一次呼叫）：

文件“exlp.py”，第54行，in

ramen, lucid, chubby = argv

ValueError:要解包的值太多

过了一会儿，我发现它是把文件名作为一个值来计算的。我不知道为什么会这样，但这是我的代码：

  from sys import argv

sakura, ramen, lucid, chubby = argv

print "You love...", sakura
print "You like to eat...", ramen
print "Your dreams are...", lucid
print "You are...", Naruto

print raw_input('Do you know someone named Naruto?')

谢谢你

Answer 1

因为那是what it does

sys.argv

The list of command line arguments passed to a Python script. argv[0] is the script name (it is operating system dependent whether this is a full pathname or not). If the command was executed using the -c command line option to the interpreter, argv[0] is set to the string '-c'. If no script name was passed to the Python interpreter, argv[0] is the empty string.

To loop over the standard input, or the list of files given on the command line, see the fileinput module.

计算该值或切片该列表：

_, ramen, lucid, chubby = argv # option 1
ramen, lucid, chubby = argv[1:] # option 2