按值分组列表索引

Question

比如：

l = [0,0,0,1,1,1,2,2,2,2,3,3]

我想要：

[[0,1,2], [3,4,5], [6,7,8,9], [10,11]]

现在，我正在做：

[[elem[0] for elem in list(g)] for k, g in itertools.groupby(
enumerate(l), lambda x: x[1])]

有没有更好更快更简单的方法

谢谢

Answer 1

这看起来很简单

result = []
last = None
for i, this in enumerate(a):
    if this != last:
        sub = []
        result.append(sub)
        last = this
    sub.append(i)