我有一个问题,提取标题,因为我设法提取 但是 它不是只针对“标题”的,它提取了其他内容作为 好 我怎样才能做一个正则表达式呢
我试过用(?)>;)([^&燃气轮机<;]+?)(?=标签也是
<rss xmlns:dc="http://purl.org/dc/elements/1.1/"
xmlns:media="http://search.yahoo.com/mrss/"
xmlns:atom="http://www.w3.org/2005/Atom"
xmlns:nyt="http://www.nytimes.com/namespaces/rss/2.0" version="2.0">
<script/>
<channel>
<title>NYT > Top Stories</title>
<link>https://www.nytimes.com?emc=rss&partner=rss</link>
<atom:link
href="https://rss.nytimes.com/services/xml/rss/nyt/HomePage.xml"
rel="self" type="application/rss+xml"/>
<description/>
<language>en-us</language>
<copyright>Copyright 2019 The New York Times Company</copyright>
<lastBuildDate>Thu, 17 Oct 2019 22:53:19 +0000</lastBuildDate>
<image>
<title>NYT > Top Stories</title>
<url>
https://static01.nyt.com/images/misc/NYT_logo_rss_250x40.png
</url>
<link>https://www.nytimes.com?emc=rss&partner=rss</link>
</image>
<item>
<title>
Mulvaney Says Trump Held Back Ukraine Aid Pending Investigation of
Democrats
</title>
<link>
https://www.nytimes.com/2019/10/17/us/politics/mick-mulvaney-trump-
ukraine.html?emc=rss&partner=rss
</link>
<guid isPermaLink="true">
https://www.nytimes.com/2019/10/17/us/politics/mick-mulvaney-trump-
ukraine.html
</guid>
<atom:link href="https://www.nytimes.com/2019/10/17/us/politics/mick-
mulvaney-trump-ukraine.html?emc=rss&partner=rss" rel="standout"/>
<description>
Undercutting President Trump’s denial of a quid pro quo, the acting
White House chief of staff told reporters that military aid was held
back in part to prod Ukraine to investigate Democrats.
</description>
<dc:creator>Michael D. Shear</dc:creator>
I
我提取所有以标题结尾的内容以及如何制作
specific that I want to extract the below mentioned part only and
not the other content
<item>
<title>
Mulvaney Says Trump Held Back Ukraine Aid Pending Investigation of
Democrats
</title>
我有可能拿到这个头衔,如果有人能帮我,那将是一个巨大的帮助,我已经挣扎了好几天了
目前没有回答
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