如何在数据帧系列中包含有关组的丢弃信息？

Question

我有下面的数据帧，我想包括所有信息的基础上“个人ID”后，条件（s）得到满足

import pandas as pd


data = [['A-1', 'Birth','0'],
        ['A-1','Sickle cell',"5"],['A-1', 'Lung cancer',"25"],
        ['A-1','Death','35'],['A-2', 'Birth', '0'],
        ['A-2','Sarcoma','10'],['A-2', 'Melanoma','19'], 
        ['A-2', 'Current Age', '20'], ['A-3', 'Birth',"0"],
        ['A-3','Sickle cell','25'],['A-3', "Skin cancer", "29"], 
        ['A-3', "Current Age", '40']]

df = pd.DataFrame(data,columns=["Individual ID", "Diagnosis","Age"])

print df

我尝试了以下代码：

first = pd.DataFrame(df.groupby("Individual ID").filter(lambda g: g["Individual ID"].size > 3))

breast1 = ((first["Repeat Instance"] == 1) & (first["Diagnosis"] != "Sickle cell"))  

after = first[breast1]

print after

运行代码后，我得到以下结果：

  Individual ID    Diagnosis Age Repeat Instance
1           A-1  Sickle cell   5               1
9           A-3  Sickle cell  25               1

我想得到个人A-1和A-3（出生，当前年龄，其他诊断）的其余信息，但还没有弄清楚

任何帮助都将不胜感激

Answer 1

我用Python的方式回答

df = pd.DataFrame(data,columns=["Individual ID", "Diagnosis","Age"])
search = '0'
a = list(filter(lambda x:x[2]==search,data))
print (a)

它返回第三个元素为0的列表，您可以自定义它