SQL查询从连接表返回数据返回错误（可能是由于我的查询语法！）

Question

我在使用python/flask从数据库中获取数据时遇到了SQL查询问题（可能是因为我对MySQL比较陌生，而且我的查询语法可能很糟糕！）

我正在尝试从数据库的桥接表中获取数据，因为它是在下面创建的：

CREATE TABLE student (
student_id int AUTO_INCREMENT,
first_name varchar (20) NOT NULL,
last_name varchar (20) NOT NULL,
year_began int NOT NULL,
PRIMARY KEY (student_id)
);

CREATE TABLE courses (
course_code varchar (7) NOT NULL,
course_title varchar (100) NOT NULL,
year_delivered int NOT NULL,
PRIMARY KEY (course_code)
);

CREATE TABLE enrollments (
student_id int NOT NULL,
course_code varchar (7) NOT NULL,
CONSTRAINT enrollment PRIMARY KEY (student_id, course_code),
FOREIGN KEY (student_id) REFERENCES student (student_id),
FOREIGN KEY (course_code) REFERENCES courses (course_code) 
);

我当前的python代码（包括我的查询）是这样编写的：

        student_name = str(request.form['student_name_search'])
        student_name = ' '.join(student_name.split())

        try:
            cursor = mydb.cursor()
            cursor.execute("SELECT student_id, first_name, last_name FROM student AND course_code FROM courses\
            LEFT JOIN enrollments on student_id=student_id LEFT JOIN course_code=course_code WHERE\
                (CONCAT(first_name,last_name ) LIKE '%{}%')".format(student_name))
            search_result = cursor.fetchall()
            cursor.close()
            return render_template('studentselect_results.html', student_name = student_name)


        except mysql.connector.Error as err:
            cursor.close()
            return failure('studentsearch',f"Error message: {err}. Search didn't work")

输入搜索条件的HTML如下：

<form action="{{ url_for('process_searchstudent') }}" method="POST">
            <div class="form-row justify-content-center">
                <div class="form-row">
                    <div class="form-group col-12">
                        <input type="text" class="form-control" id="student_name_search" name="student_name_search" 
                        placeholder="Enter Students Name">
                    </div> 
                </div>
            </div>   
            <!-- SUMBIT/RESET BUTTONS-->
            <div class="form-row justify-content-center">
                <div class="form-group row">
                    <div class="form-group">
                        <input type="submit" class="btn btn-outline-success" value="Search">
                        <input type="button" id="resetBtn" class="btn btn-outline-danger" value="Reset">
                    </div>
                </div>
            </div>
        </form>

我希望查询返回数据的HTML如下：

<table class="table table-sm table-striped">
        <thread class="thread-light">
            <tr>
                <th>Student ID:</th>
                <th>Student First Name:</th>
                <th>Student Last Name:</th>
                <th>Click to View Student Details</th>
            </tr>
        </thread>
        <tbody>
            {% for each_result in search_results %}
            <tr>
                <td>{{item[0]}}</td>
                <td>{{item[1]}}</td>
                <td>{{item[2]}}</td>
            </tr>
            {% endfor %}
        </tbody>
    </table>

在第一个HTML页面上单击“搜索”按钮时，会出现以下错误：

错误消息：1064（42000）：您的SQL语法有错误；请查看与您的MySQL服务器版本对应的手册，以获取正确的语法，以便在第1行中使用near'和course\u code FROM courses LEFT JOIN registrations on student\u id=stud'。搜索不起作用

任何帮助都将不胜感激

Answer 1

这不是JOIN查询的正确语法。请尝试以下操作：

SELECT s.student_id, s.first_name, s.last_name , c.course_code
FROM student s
LEFT JOIN enrollments e on e.student_id = s.student_id
JOIN courses c ON c.course_code = e.course_code 
WHERE CONCAT(s.first_name, s.last_name) LIKE '%{}%'