在函数Python中使用刮削数

Question

我怎样才能打开一个擦掉的数据点23FLAT

soup = BeautifulSoup(response, 'html.parser')
datapoint_one = soup.findAll(class_ = 'kinfobox').text
just_number = float(datapoint_one.strip('FLAT'))
print(just_number)
.. 23

使用它

amount = '200'
for number in numbers:
    ((just_number*int('1000'))+int(amount))

这样我就可以在它上面迭代amount多次

就像这样

23200
23400
23600
...

Answer 1

基于你在评论中的问题。你可以这样做

假设要生成n个数字。 所以

numbers =n
amount = '200'
your_text = "23FLAT"
just_number = your_text.strip("FLAT")
initial_number = int(just_number+amount)
amount_int = int(amount)
for i in range(numbers):
    print(initial_number + i*amount_int)