我有一个保存列表的函数,函数如下所示:
def call_openNMS_service(node):
print node
打印节点的输出为
{'ip': [u'10.21.204.174', u'10.21.205.148', u'10.21.50.153', u'10.21.50.192', u'10.21.50.198', u'10.21.51.149', u'10.21.51.158', u'10.21.51.200', u'10.21.51.252', u'10.21.52.202', u'10.21.52.53', u'10.21.54.12', u'10.21.54.149', u'10.21.55.132', u'10.21.55.176', u'10.21.55.239', u'10.21.56.169', u'10.21.56.48', u'10.21.65.106', u'10.21.65.125', u'10.21.65.34', u'10.21.67.131', u'10.21.67.179', u'10.21.67.194', u'10.21.67.230', u'10.21.67.249', u'10.21.67.45', u'10.21.67.70', u'10.21.68.127', u'10.21.68.180', u'10.21.68.73', u'10.21.69.200', u'10.21.69.38', u'10.21.70.121', u'10.21.70.56'],
'id': [u'564', u'561', u'462', u'389', u'352', u'353', u'390', u'354', u'356', u'454', u'348', u'349', u'455', u'563', u'359', u'360', u'363', u'362', u'525', u'426', u'503', u'466', u'431', u'527', u'529', u'373', u'414', u'518', u'430', u'425', u'413', u'368', u'404', u'517', u'502']}
现在,我必须选择第一个IP和第一个ID,然后将其传递到URL,如下所示:>
http://localhost:8980/opennms/rest/nodes/564/i接口/10.21.204.174/services
其他人也一样。怎么做
您可以
zip
将dict值放在一起,然后在列表理解中使用str.format
来构建您的url相关问题 更多 >
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