Python日期时间相减而忽略周末

Question

我熟悉Python中从当前日期减去天数的timedelta方法（见下文）；不过，我很好奇我怎么能让它自动跳过周末

from datetime import datetime, timedelta
target_date = datetime.today() - timedelta(days=dayoffset)

例如，2019-10-08减去3天就是2019-10-03（因为第5天和第6天是周末）。谢谢你

Answer 1

您可以尝试datetime.weekday()，它将日期返回到0-6之间的值，而5和6是周末

Read more on this.

from datetime import datetime, timedelta
def diff_day(start, end):
    delta = timedelta(days=1)
    d = start
    diff = 0
    weekend = [5, 6]
    while d < end:
        if d.weekday() not in weekend:
            diff += 1
        d += delta
    return diff

>>>start = datetime(2019,10,3)
>>>end = datetime(2019,10,8)
>>>diff_day(start, end)
3