将Python的向量列表结果重新格式化为一个逗号分隔

Question

如何将向量数组（Python）的结果reformat转换为单个逗号分隔的结果

我有这些结果：

   [ ['44231#0:', '2016/10/11', '11:19:23', '11:19:23', '1', '11:19:24', '11:19:24'
, '0']
 ['44231#0:', '2016/10/11', '12:20:39', '12:20:58', '12:20:59', '12:20:59', '0']
]

我需要这样的东西：

44231#0:, 2016/10/11, 11:19:23, 11:19:23, 1, 11:19:24, 11:19:24
44231#0:, 2016/10/11, 12:20:39, 12:20:58, 12:20:59, 12:20:59, 0

有人吗

提前谢谢

Answer 1

简单的方法是使用两个for循环

for d in data:
    s = ''
    for l in d:
        s += l + ', '
    print(s[:-2])

Answer 2

你想列一个字符串列表吗？执行：

[', '.join(sublist) for sublist in data]