从其他函数调用函数

Question

我很难让这个程序正常工作，因为输入是TypeError: 'int' object is not callable

#!/usr/bin/python3



def displaymenu():

    input32=int(input("1)  Run experiment\n2) Exit"))
    return input32  
def cal1(we,woc,wa):

    wala=we*woc(wa-woc)
    return wala

def cal2(wo,woh):

    wolo=24*wo*woh*wa
    return wolo

def cal3(wa,woc):

    wele=wa**2+woc(wa-woc)
    return wele

def beamere(wala,wolo,wele):

    y=(wala/wolo)*wele
    return y

input32 = displaymenu()
while input32 is not 2:

    if input32 == 1:
        we= int(input("enter your width"))
        wo= int(input("enter what ever this is"))
        woh=int(input("enter this thing"))
        wa= int(input("i really should stop calling my varibles random sylibles"))
        woc=int(input("enter your woc"))
        wala  =  cal1(we,woc,wa)
        wolo  =  cal2(wo,woh)
        wele  =  cal3(wa,woc)
        y     =  beamere(wala,wolo,wele)
        print(y)



    elif input32 == 2:


        print("learn english")
        break
    else:
        input32 = displaymenu()

Answer 1

这是由于您的cal1和cal3： 在执行wala=we*woc(wa-woc)时，您告诉python使用woc作为函数，您可能打算使用wala=we*woc*(wa-woc)将woc乘以(wa-woc)。第二个函数也是如此

以下是您的函数的外观：

def cal1(we,woc,wa):

    wala=we*woc(wa-woc)
    return wala

def cal3(wa,woc):

    wele=wa**2+woc(wa-woc)
    return wele

Answer 2

在函数def cal1中修改行 从

wele=wa**2+woc(wa-woc)

至

wele=wa**2+woc*(wa-woc)

woc（wa woc）—>；指示参数为“wa woc”的woc函数调用