我有一个1000本字典的列表,每本字典包含url,文件名
for di in images_to_download:
temp = download_image(di['img_url'],di['image_full_name'])
if not temp:
continue
upload_file(temp,t4['id'])
def download_image(img_url,image_full_name)
try:
req = request(img_url, headers=headers)
raw_img = urlopen(req).read()
try:
with open(image_full_name,'wb') as file:
file.write(raw_img)
except:
image_full_name = query+str(random.randint(100000))
with open(image_full_name,'wb') as file:
file.write(raw_img)
return image_full_name
except Exception as e:
print ("Download failed: {}".format(e))
return None
def upload_file(file_name,folder_id):
file2 = drive.CreateFile({'parents': [{'id': folder_id}]})
file2.SetContentFile(file_name)
file2.Upload()
这是我的代码到目前为止,它工作得很好,但它是缓慢的(3-6秒每幅图像),所以我想线程它我怎么能做到这一点
图片来自不同的网站,所以我可以下载他们没有太快的要求在网站上
目前没有回答
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