Djang中QuerySet中特定列的平均重复数

2024-05-26 21:51:35 发布

您现在位置:Python中文网/ 问答频道 /正文

我使用的Django模型如下所示:

class FinancialAid(models.Model):
    RECEIVED_EVERY = (("J", "Jours"),
        ("S", "Semaines"),
        ("M", "Mois"))
    ID = models.AutoField(primary_key=True)
    Name = models.CharField(max_length=100, null=True, blank=True)
    Value = models.IntegerField(null=True, blank=True, default=-1)
    ReceivedEvery = models.CharField(max_length=15, null=True, blank=True, choices=RECEIVED_EVERY)
    Exchange = models.ForeignKey('Exchange', on_delete=models.CASCADE)

我可以访问我想要的信息,但我有一个问题,我经常在我的QuerySet中的NameReceivedEvery列上有重复项,但不总是在Value上,从不在Exchange

假设我扩展了以下查询集:

financial_aid_qs = [
    (ID=1, Name="Aid1", Value=100, ReceivedEvery="M", Exchange=Exchange.objects.get(pk=1)),
    (ID=2, Name="Aid2", Value=200, ReceivedEvery="S", Exchange=Exchange.objects.get(pk=2)),
    (ID=3, Name="Aid1", Value=150, ReceivedEvery="M", Exchange=Exchange.objects.get(pk=3)),
    (ID=4, Name="Aid3", Value=100, ReceivedEvery="M", Exchange=Exchange.objects.get(pk=4))
]

如您所见,对于索引1和索引3,我有相同的NameReceivedEvery。我想做的是获得一个QuerySet(或者ValuesQuerySet,尽管我似乎记得它被删除了),它将包含所有不同的FinancialAid对象,并平均出具有相同Name的FinancialAid对象的Value。理想情况下,它会考虑到这样一个事实,即ReceivedEvery可以不同,即使Name是相同的(这都是一个平均值,因此不需要完美,这就是为什么一个月是30天或4周)

有了这些,结果应该是这样的:

financial_aid_qs = [
    (Name="Aid1", Value=125, ReceivedEvery="M"),
    (Name="Aid2", Value=200, ReceivedEvery="S"),
    (Name="Aid3", Value=100, ReceivedEvery="M")
]

如您所见,对于Aid1,该值已从100和150平均为125,而其他辅助工具尚未修改


Tags: nameidtruegetobjectsexchangevaluemodels
1条回答
网友
1楼 · 发布于 2024-05-26 21:51:35

使用^{}对分组查询进行聚合,例如:

financial_aid_qs = FinancialAid.objects.values("Name").annotate(avg_value=Avg("Value"))

这将返回字典的查询集(在执行列表时):

financial_aid_qs = [
    {'Name': "Aid1", 'avg_value': 125},
    {'Name': "Aid2", 'avg_value': 200},
    ...
]

如果您还想通过ReceivedEvery进行区分,那么您只需根据两个值进行分组:

financial_aid_qs = FinancialAid.objects.values('Name', 'ReceivedEvery').annotate(...)

>>> [{'Name': "Aid1", 'ReceivedEvery': "M", 'avg_value': 125}, 
     {'Name': "Aid1", 'ReceivedEvery': "S", 'avg_value': 200}, ...]

在这里,每周和每月的捐款将分开为同一个“名字”

使用conditional expression根据其他值创建新值:

financial_aid_qs = FinancialAid.objects.annotate(
    factor=Case(
        When(ReceivedEvery="S", then=Value(4)),
        When(ReceivedEvery="M", then=Value(1)),
        output_field=IntegerField()
    )).annotate(
        total=F('factor')*F('Value')
    ).values('Name').annotate(
        avg_value=Avg('total')
    )

相关问题 更多 >

    热门问题