获取用户输入的数字并将其转换为单词？

Question

所以我的问题是让用户输入几个小时，而不是我列出一个巨大的单词列表，如果用户输入1变成“1”之类的话。我觉得我应该使用流行音乐，但同时，我觉得我将如何能够得到用户的输入，从列表中得到一个特定的字

def work(hourly, minuted):

    hour = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve"]

    newHour = hourly.pop[]

    if minuted == '0':
        print(hourly + " O'clock.")

    elif minuted <= '10':
        print("it is " + minuted + "  past " + hourly)

    elif minuted == '30':
        print("Half past " + hourly)

    elif minuted >= '35':
        print("quarter past " + hourly)


def main():

    hour = str(input("Please enter the hour: "))

    minute = str(input("Please enter the minutes: "))




main()

Answer 1

将输入转换为整数，然后使用它们索引已有的数组。简化示例：

hours = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve"]

hour = int(input("Please enter the hour: "))

print(hours[hour-1]  + " O'clock")
# Subtract one from hour because arrays start at index 0 but hours starts at "one"