擅长:python、mysql、java
<p>正确的代码是:</p>
<pre><code>for line in out.splitlines():
if FAILURE_MSGS[APPLE] in line and "banana" in line:
<do something special with this line>
</code></pre>
<p>代码的作用:</p>
<ul>
<li>如果失败,由于每个非空字符串
是真的</li>
<li>if“banana”in line仅在banana in line时返回true</li>
</ul>
<p>所以你会得到所有行有“香蕉”而不管“苹果”</p>