正在创建Django冗余迁移文件

Question

class Agency(models.Model):
   uuid = models.UUIDField(editable=False, default=uuid.uuid4())
   name = models.CharField(
    verbose_name='Name',
    max_length=50
)

每当我应用python manage.py makemigrations时，就会创建新的迁移文件。值得一提的是，我没有接触models.py文件

迁移文件内容无效

class Migration(migrations.Migration):

dependencies = [
    ('dashboard', '0001_initial'),
]

operations = [
    migrations.AlterField(
        model_name='agency',
        name='uuid',
        field=models.UUIDField(default=uuid.UUID('890eb162-c485-49f0-87a6-ebc3e95a12b3'), editable=False),
    ),
    migrations.AlterField(
        model_name='agencycontract',
        name='uuid',
        field=models.UUIDField(default=uuid.UUID('f6500cbe-69ee-42c0-ad1e-80377f2a9dcf'), editable=False),
    ),
    migrations.AlterField(
        model_name='contractproduct',
        name='uuid',
        field=models.UUIDField(default=uuid.UUID('7bc66e61-c752-4333-b508-14b53c903e83'), editable=False),
    ),
]

我知道，因此我使用uuid函数，这就是为什么要创建这些函数。如何停止文件创建？在此之前，是否真的有必要停止此迁移文件的创建

Answer 1

用途：

models.UUIDField(editable=False, default=uuid.uuid4)  # Instead of uuid.uuid4()