替换字符串的Python正则表达式

Question

如何使用RegEx（或者Python中的其他东西）满足以下需求？ 我需要：

1. 去掉“梦”这个词（包括它的所有词干）
2. 删除前面的所有单词（即“梦想”后面的所有单词）
3. 删除它旁边的单词（在它前面/在“梦”的右边）
4. 从所有短语中删除“to”

输入：

text = ["Dream of a car",
        "Dream to live in a world",
        "Dream about 8am every morning",
        "stopped dreaming today",
        "still dreaming of a car",
        "One more dream to come late tomorrow",
        "Dream coming to hope tomorrow"]

所需输出：

["a car",
 "live in a world",
 "8am every morning",
 " ",
 "a car",
 "come late tomorrow",
 "hope tomorrow"]

我试过：

result = [re.sub('Dream', '', a) for a in text]

# MyOutput
[' of a car', ' to live in a world', ' about 8am every morning', 'stopped dreaming today', 'still dreaming of a car', 'One more dream to come late tomorrow', ' coming to hope tomorrow']

Answer 1

这将提供所需的输出

result = [re.sub(r'\bto\b *', '', re.sub(r'^.*Dream[^ ]* *[^ ]* *', '', a, flags=re.I)) for a in text]

如果你只想移除前面的to

result = [re.sub(r'^.*Dream[^ ]* *[^ ]* *(\bto\b)? *', '', a, flags=re.I) for a in text]