python替换di中json数据中的多个键

Question

可以从json文件替换dict中的多个键吗。 我将尝试用简单的例子来解释我的问题： 我有这样一个json文件：

   "a1": {
      "option": "2",
      "suboption": "2",
      "option": "2",
      "suboption_device": "3",
      "option": "1",
      "suboption_ip": "1",
      "option": "1",
      "suboption_ip": "2"
    }

我的第一次测试是这样的：

def replace_option(match):
    global o
    o += 1
    return 'option%o' % o

def replace_suboption(match):
    global s
    s += 1
    return 'suboption%s' % s

def preProcessing():
    with open('test.json') as f:    
        data = f.read()
    replace1 = json.loads(re.sub("option", replace_option, data))
    replace2 = json.loads(re.sub("suboption", replace_suboption, data))

所以在replace1中，除了一个，所有的suboption_ip和replace2中，所有的option都消失了

嗯。。。也许可以用一种方法来执行替换过程？有什么想法吗

谢谢你帮我：）

编辑：

从replace1输出：

"a1": {
  "option1": "2",
  "suboption": "2",
  "option2": "2",
  "suboption_device": "3",
  "option3": "1",
  "suboption_ip": "1",
  "option4": "1",
}

从replace2输出：

"a1": {
  "option": "2",
  "suboption1": "2",
  "suboption2_device": "3",
  "suboption3_ip": "1",
  "suboption4_ip": "2"
}

Answer 1

使用方便：

with open(INFILE, "rt") as f:    
    with open(OUTFILE_BLOCK, "wt") as o:
        for line in f:
            i += 1
            o.write(line.replace("pn_dcp.block", "pn_dcp.block%i" %i))
i = 0
with open(OUTFILE_BLOCK, "rt") as f:    
    with open(OUTFILE_OPTION, "wt") as o:
        for line in f:
            i += 1
            o.write(line.replace("pn_dcp.option", "pn_dcp.option%i" %i))
i = 0
with open(OUTFILE_OPTION, "rt") as f:    
    with open(OUTFILE_FINAL, "wt") as o:
        for line in f:
            i += 1
            o.write(line.replace("pn_dcp.suboption", "pn_dcp.suboption%i" %i))
i = z