我们的任务是做海龟图书馆在没有图书馆的情况下会做的事情
这是我得到的图纸 它需要用for循环跟踪路径,但不应该到达它开始的同一个位置,因为旋转角度应该使海龟每次降落在不同的点上。顺便说一句,德雷查(右),伊兹奎尔达(左),阿里巴(上)阿巴霍(下)
from graphics import*
import math
ancho = 500
alto = 500
a=alto/2
b=ancho/2
win = GraphWin ("Estrella",ancho,alto)
origen=Point(ancho/2, alto/2)
dirTort="derecha"
def T(dir,dist,ang):
global dirTort,a,b
ang=ang*math.pi/180
for i in range (40):
if dir == "derecha":
if dirTort == "derecha":
dirTort = "abajo"
valx = math.cos(ang)
valy = math.sin(ang)
elif dirTort == "izquierda":
dirTort = "arriba"
valx = -math.cos(ang)
valy = -math.sin(ang)
elif dirTort == "arriba":
dirTort = "derecha"
valx = math.sin(ang)
valy = -math.cos(ang)
elif dirTort == "abajo":
dirTort = "izquierda"
valx = -math.sin(ang)
valy = math.cos(ang)
elif dir == "izquierda":
if dirTort == "derecha":
dirTort = "abajo"
valx = -math.cos(ang)
valy = -math.sin(ang)
elif dirTort == "izquierda":
dirTort = "arriba"
valx = -math.cos(ang)
valy = math.sin(ang)
elif dirTort == "arriba":
dirTort = "derecha"
valx = -math.sin(ang)
valy = -math.cos(ang)
elif dirTort == "abajo":
dirTort = "derecha"
valx = math.sin(ang)
valy = math.cos(ang)
p1 = Point(a, b)
coordx=a+dist*valx
coordy=b+dist*valy
p2=Point(coordx, coordy)
linea=Line(p1,p2)
linea.setFill("red")
linea.draw(win)
a=coordx
b=coordy
print(coordx,coordy)
T("derecha",200,10)
print(dirTort)
message = Text(Point(win.getWidth()/2,win.getHeight()/15),"Click para salir")
message.draw(win)
win.getMouse()
我认为你没有正确把握你的角度。因为你基本上是反复画一个正方形,每次旋转一点,你的角度是90度,或者-90度。通过传递到函数中的小旋转角度,在正方形之间稍微倾斜。下面是一个高度简化的代码版本,用于绘制所需的目标:
希望它能帮助你让你的代码回到正轨
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