获取字典中函数值的几个问题

Question

所以，我刚开始使用Python，但是我尝试在字典中实现函数（有点像C中的函数指针），但是我仍然停留在如何在没有错误的情况下接收函数返回的值上。下面是我代码中的一个小片段：

def main():
    numberOfDice = 5
    dice = rollDice(numberOfDice) #rolls dice thrice, returns a list of 5 integers
    scoreBoard(dice)   #displays Yahtzee scoreboard
    value = choice(dice)  #value = the category choice[1-13]
    whichCategory(value) 

def whichCategory(category):
    board = {
        6: numberOfSixes, # I have 1-13 filled, but just for example
        12: yahtzee       # this is just to save space.
        }
    board[category]()

def numberOfSixes(theDice):
    count = theDice.count(6)
    points = count * 6

    return points

def yahtzee(theDice):
    yahtzee = 0
    ones, twos, threes, fours, fives, sixes = countDice(theDice)
    # countDice() determines the amount that each number is present in the 
    # list and then returns those six variables.
    if any(x==5 for x in(ones, twos, threes, fours, fives, sixes)):
           yahtzee = 50

    return yahtzee

在滚动三次并最终确定骰子（整数列表）之后，我从whichCategory（）的选项中选择我的值，然后它进行正确的计算，从这些函数中吐出正确的返回值，但是我会得到这样的错误（输入两个6（12分））：

Traceback (most recent call last):
File "C:\python\Lib\idlelib\Yahtzee.py", line 407, in <module>
main()   # My call to main()
File "C:\python\Lib\idlelib\Yahtzee.py", line 18, in main
whichCategory(value)
File "C:\python\Lib\idlelib\Yahtzee.py", line 90, in whichCategory
board[category]()
TypeError: yahtzee() missing 1 required positional argument: 'theDice

有趣的是，它说的错误是yahtzee（），而不是6，我相信这是因为它以某种方式得到了12作为答案，并调用了字典中的第12个关键字。否则我会得到这样一个错误：

Traceback (most recent call last):
File "C:\python\Lib\idlelib\Yahtzee.py", line 407, in <module>
main()   # My call to main()
File "C:\python\Lib\idlelib\Yahtzee.py", line 18, in main
whichCategory(value)
File "C:\python\Lib\idlelib\Yahtzee.py", line 90, in whichCategory
board[category]()
KeyError: 50

拜托，我已经找过答案了，但还没找到。如果可能的话，我想把字典中函数的值返回main（）。任何帮助都将不胜感激

Answer 1

这是未经测试的，但我认为问题是在board[category]()行，您调用了一个函数，但没有使用它所需的值。尝试进行这些更改

def main():
    numberOfDice = 5
    dice = rollDice(numberOfDice) #rolls dice thrice, returns a list of 5 integers
    scoreBoard(dice)   #displays Yahtzee scoreboard
    value = choice(dice)  #value = the category choice[1-13]
    whichCategory(value, dice) # pass dice

def whichCategory(category, dice):  # receive dice
    board = {
        6: numberOfSixes, # I have 1-13 filled, but just for example
        12: yahtzee       # this is just to save space.
        }
    board[category](dice)   # call with dice