Python比较contains和showing匹配的两个dicts值

Question

我可以看到很多类似的问题，但我没有太多的运气找到答案

我有两个字典的值，我想匹配，但不同的键。我尝试了一个匹配查询，但它返回空的。我想可能是因为找不到匹配的关键字？或者不迭代k，v对？但我不知道该怎么办

interface_list = [
        {'ifIndex': 19, 'Caption': 'GigabitEthernet0/0/0 *** Uplink ***', 'ifType': 131, 'ifSubType': 0, 'InterfaceID': 0, 'Manageable': True, 'ifSpeed': 0.0, 'ifAdminStatus': 0, 'ifOperStatus': 4},
        {'ifIndex': 19, 'Caption': 'GigabitEthernet0/0/1', 'ifType': 131, 'ifSubType': 0, 'InterfaceID': 0, 'Manageable': True, 'ifSpeed': 0.0, 'ifAdminStatus': 0, 'ifOperStatus': 4},
        {'ifIndex': 19, 'Caption': 'GigabitEthernet0/0/2', 'ifType': 131, 'ifSubType': 0, 'InterfaceID': 0, 'Manageable': True, 'ifSpeed': 0.0, 'ifAdminStatus': 0, 'ifOperStatus': 4},
        {'ifIndex': 19, 'Caption': 'Tunnel100', 'ifType': 131, 'ifSubType': 0, 'InterfaceID': 0, 'Manageable': True, 'ifSpeed': 0.0, 'ifAdminStatus': 0, 'ifOperStatus': 4},
        {'ifIndex': 20, 'Caption': 'Vlan5', 'ifType': 53, 'ifSubType': 0, 'InterfaceID': 0, 'Manageable': True, 'ifSpeed': 0.0, 'ifAdminStatus': 0, 'ifOperStatus': 4},
        {'ifIndex': 21, 'Caption': 'Vlan10', 'ifType': 53, 'ifSubType': 0, 'InterfaceID': 0, 'Manageable': True, 'ifSpeed': 0.0, 'ifAdminStatus': 0, 'ifOperStatus': 4},
        {'ifIndex': 22, 'Caption': 'Vlan15', 'ifType': 53, 'ifSubType': 0, 'InterfaceID': 0, 'Manageable': True, 'ifSpeed': 0.0, 'ifAdminStatus': 0, 'ifOperStatus': 4},
]

wanted_interfaces = [{'resource': 'GigabitEthernet0/0/0'}, {'resource': 'Vlan5'}]

>>> matches = [i for str(i) in wanted_interfaces if i in interface_list]
>>> matches
[]

它应该有希望返回包含“GigabitEthernet0/0/0*Uplink*”的记录作为匹配

Answer 1

要进行全面扫描（假设要检查两个列表中每个dict中的每个值），必须执行以下操作：

matches = [
    v for d1 in interface_list for v in d1.values() 
    if any(isinstance(v, str) and vw in v for d2 in wanted_interfaces for vw in d2.values())
]
# ['GigabitEthernet0/0/0 *** Uplink ***']