Python正则表达式查找和重新定位单词

Question

已解决

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我以前一直在使用console.snips.ai控制台来制作和培训我的助手，但现在我希望在本地自行运行它，而不使用所有其他功能，并且需要更改控制台提供给您的导出文件的格式。它需要从：how tall is [Bill Gates](queryObject) [uncle](relations)更改为how tall is [queryObject](Bill Gates) [relations](uncle)，然后可以很容易地将其转换为所需的yaml格式

到目前为止，我已经能够用下面一些非常长的代码来翻转实体-queryObject和实体示例Bill Gates周围的括号类型，但是我正在努力翻转(Bill Gates)和[queryObject]的位置，其中有一个最近的括号，Bill Gates和queryObject可以交换，而relations和uncle也可以交换

string_ = "how tall is [Bill Gates](queryObject) [uncle](relations)"

nStr = list(string_)

for i , char in enumerate(nStr):

if char == "[":

    nStr[i] = "{"

if char == "]":

    nStr[i] = "}"

if char == "(":

    nStr[i] = "["

if char == ")":

   nStr[i] = "]"

for j , char in enumerate(nStr):

    if char == "{":

        nStr[j] = "("

    if char == "}":

        nStr[j] = ")"

new = ''.join(nStr)

print(new)

所以这成功地把how tall is [Bill Gates](queryObject) [uncle](relations)变成了how tall is (Bill Gates)[queryObject] (uncle)[relations]

但是我如何用离它最近的[]翻转()的位置

更新

这就是现在发生的事情

Answer 1

参考文献： regex matching any character including spaces

代码：

import re
new = 'how tall is [Bill Gates](queryObject) [uncle](relations)'
result = (re.sub(r'(\[.*?\])(\(.*?\))', r'\2\1', new))
print(result)

将更改：

how tall is [Bill Gates](queryObject) [uncle](relations)

收件人：

how tall is (queryObject)[Bill Gates] (relations)[uncle]

Answer 2

将re.sub()与反向引用一起使用：

import re

s = 'how tall is [Bill Gates](queryObject) [uncle](relations)'

result = re.sub(r'\[(.*?)\]\((.*?)\)', r'[\2](\1)', s)

# how tall is [queryObject](Bill Gates) [relations](uncle)