我有三个模型,冰箱,食谱和配料,我想得到所有食谱的查询集,并将它们的配料与冰箱对象中的食物内容进行比较。我想过滤掉所有的食谱,其中没有匹配的成分,我的食物内容和返回查询集只匹配
冰箱和食物都在一个应用程序中,食谱和配料在另一个应用程序中
我对Django还很陌生,我没能找到一个方法。我只使用搜索输入过滤出菜谱,但那只是一个单词
class Fridge(models.Model):
name = models.CharField(max_length=20)
belongs_to = models.ForeignKey(User, related_name="my_fridge", on_delete=models.CASCADE)
food_contents = models.ManyToManyField(Food, related_name="in_fridges")
slug = models.SlugField(allow_unicode=True, unique=True)
class Food(models.Model):
name = models.CharField(max_length=20, unique=True)
quantity = models.PositiveIntegerField()
description = models.TextField(max_length=255, blank=True)
date_added = models.DateTimeField(default=timezone.now)
expiration_date = models.DateTimeField()
is_expired = models.BooleanField(default=False)
slug = models.SlugField(allow_unicode=True, unique=True)
class Recipe(models.Model):
name = models.CharField(max_length=255, unique=True)
rating = models.CharField(max_length=255)
preparation_time = models.CharField(max_length=255)
servings = models.CharField(max_length=255)
instructions = models.CharField(max_length=1000)
slug = models.SlugField()
class Ingredient(models.Model):
name = models.CharField(max_length=255)
recipe = models.ForeignKey(Recipe, related_name="ingredients", on_delete=models.CASCADE)
目前没有回答
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