Python：如何从最后的输入返回到游戏的开始？

Question

所以我对编程很陌生，在谷歌的帮助下做了一个小游戏。游戏的第一个代码是有效的，但是我想问我如何添加一个函数来询问我是否想再玩一次，例如，如果我说“是”，那么它会再次玩游戏，并返回到“我在想一个数字…”或者如果我说“否”，那么它会退出

第二个代码是不起作用的代码，我尝试添加一个函数让游戏再次运行，并建议我添加另一个while循环，但不太确定放在哪里。目前第二个代码，当我猜到正确的数字，它只是关闭，不要求输入

我为这个愚蠢的问题道歉，但我想不通

import random

guessesTaken = 0

print("Hello, I am your computer. What is your name?")
myName = input()

number = random.randint(1, 20)
print("\nHello " + myName + ", and welcome to the game! Do you want to play?")
playGame = input()

while playGame == "Yes":
    print("I am thinking of a number between 1 and 20, can you guess my number?\n")

    while guessesTaken < 6:
        print("Take a guess. ")
        guess = input()
        guess = int(guess)

        guessesTaken += 1

        if guess < number:
            print("Your guess is too low.")

        if guess > number:
            print("Your guess is too high.")

        if guess == number:
            break

    if guess == number:
        guessesTaken = str(guessesTaken)
        print("Well done " + myName + "! You guessed my number in " + guessesTaken + " guesses!")

    if guess != number:
        number = str(number)
        print("Sorry " + myName + ", but you couldn't figure it out, my number was " + number)
    break

while playGame == "No":
    print("Then you opened this for nothing, goodbye")
    break
input()

import random

guessesTaken = 0

print("Hello, I am your computer. What is your name?")
myName = input()

number = random.randint(1, 20)
print("\nHello " + myName + ", and welcome to the game! Do you want to play?")
playGame = input()

while playGame == "Yes" or playAgain == "Yes":
    print("I am thinking of a number between 1 and 20, can you guess my number?\n")

    while guessesTaken < 6:
        print("Take a guess. ")
        guess = input()
        guess = int(guess)

        guessesTaken += 1

        if guess < number:
            print("Your guess is too low.")

        if guess > number:
            print("Your guess is too high.")

        if guess == number:
            break

    if guess == number:
        guessesTaken = str(guessesTaken)
        print("Well done " + myName + "! You guessed my number in " + guessesTaken + " guesses! \nWould you like to play again?")
        playAgain = input()

    if guess != number:
        number = str(number)
        print("Sorry " + myName + ", but you couldn't figure it out, my number was " + number + "\nWould you like to play again?")
        playAgain = input()
    break

while playAgain == "No":
    print("Thank you for playing, goodbye")
    break

while playGame == "No":
    print("Then you opened this for nothing, goodbye")
    break
input()

Answer 1

您可以将播放特性添加为函数，并在while循环中调用它

import random    


def PlayGame():
    guessesTaken = 0

    print("Hello, I am your computer. What is your name?")
    myName = input()

    number = random.randint(1, 20)
    print("\nHello " + myName + ", and welcome to the game!")
    print("I am thinking of a number between 1 and 20, can you guess my number?\n")

    while guessesTaken < 6:
        print("Take a guess. ")
        guess = input()
        guess = int(guess)

        guessesTaken += 1

        if guess < number:
            print("Your guess is too low.")

        if guess > number:
            print("Your guess is too high.")

        if guess == number:
            break

    if guess == number:
        guessesTaken = str(guessesTaken)
        print("Well done " + myName + "! You guessed my number in " + guessesTaken + " guesses!")

    if guess != number:
        number = str(number)
        print("Sorry " + myName + ", but you couldn't figure it out, my number was " + number)

    print("Would you like to play again? Enter 1 for Yes and 2 for No")
    playAgain = input()
    if playAgain == 1:
        return True
    else:
        return False



playing = True

while playing == True:
    playing = PlayGame()