Python在多行上搜索文本

Question

import os
searchquery = 'word'
with open('Y:/Documents/result.txt', 'w') as f:
for filename in os.listdir('Y:/Documents/scripts/script files'):
    with open('Y:/Documents/scripts/script files/' + filename) as currentFile:
        for line in currentFile:
            if searchquery in line:
                start = line.find(searchquery)
                end = line.find("R")
                result = line[start:end]
                print result
                f.write(result + ' ' +filename[:-4] + '\n')

现在这个方法可以很好地搜索“word”并打印单词后面的所有内容，直到一个“R”，前提是它在同一行上。然而，如果“R”在这条线上，它就不会打印之前的内容

例如：

this should not be printed!
this should also not be printed! "word" = 12345
6789 "R" After this R should not be printed either!

在上述情况下，第3行的6789将不会打印我的当前。不管我想怎样。如何使python不断地遍历多行，直到到达“R”

谢谢你的帮助

Answer 1

它不在下一行打印内容是正常的，因为您正在一行中搜索单词。更好的解决办法如下

import os
searchquery = 'word'
with open('Y:/Documents/result.txt', 'w') as f:
    for filename in os.listdir('Y:/Documents/scripts/script files'):
        with open('Y:/Documents/scripts/script files/' + filename) as currentFile:              
            content = ''.join([line for line in currentFile])
            start = content.find(searchquery)
            end = content.find("R")
            result = content[start:end].replace("\n", "")
            print result
            f.write(result + ' ' +filename[:-4] + '\n')

请注意，这只适用于一次事故。您需要将其进一步分解以打印多个事件