我把dict的值以列表的形式存储起来。 下面是它的样子:
d = [
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p'},
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s'}
]
在这里,在键Length
中,我有两个值。first=steven,initial=s
我想拆分这些值并创建两个新字段,并将其以更新的形式存储在字典中。你知道吗
所需输出:
d = [
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p','first':'prince','initial':'p'},
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s','first':'steven','initial':'s'}
]
以下是我尝试的程序:
d = [
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p'},
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s'}
]
field_to_split = "Length"
split_using1 = ','
split_using2 = '='
b =[]
for i in d:
s = i[field_to_split].split(split_using1)
print(s)
b.append(s)
#print(s)
print(b)
我怎样才能做到这一点。。。你知道吗
使用简单的迭代。你知道吗
例如:
输出:
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