指定简单变量命名后出现KeyError

Question

我很长时间没有使用python了，我正试图通过一个网站从ESPN的梦幻足球网站上搜集一些信息。我使用的wesbite是https://stmorse.github.io/journal/espn-fantasy-v3.html。当我尝试下面列出的代码时，我得到KeyError:'schedule'。你知道吗

我试着完全按照网站上的代码，它给出了相同的错误。我打开了https://fantasy.espn.com/apis/v3/games/ffl/seasons/2019/segments/0/leagues/14380834?view=mMatchup上的api，看到有一个地方可以安排日程，所以不确定还需要做什么。你知道吗

league_id = 14380834
year = 2019
url = "https://fantasy.espn.com/apis/v3/games/ffl/seasons/2019/segments/0/leagues/14380834/"

r = requests.get(url)
d = r.json()
r = requests.get(url, params={"view": "mMatchup"})

df = [[
        game['matchupPeriodId'],
        game['home']['teamId'], game['home']['totalPoints'],
        game['away']['teamId'], game['away']['totalPoints']
    ] for game in d['schedule']]
df = pd.DataFrame(df, columns=['Week', 'Team1', 'Score1', 'Team2', 'Score2'])
df['Type'] = ['Regular' if w<=14 else 'Playoff' for w in df['Week']]
df.head()

我的预期结果将是5个专栏，我呼吁一周得分2通过espn网站填充。你知道吗

回溯是：

File "C:/Users/jacob/PycharmProjects/FF_stuff/app.py", line 15, in <module>
    ] for game in d['schedule']]
KeyError: 'schedule'

Process finished with exit code 1

Answer 1

您需要从包含param的请求获取jsond，而不是第一个请求。你知道吗

这很管用

r = requests.get(url, params={"view": "mMatchup"})
d = r.json()

df = [[
        game['matchupPeriodId'],
        game['home']['teamId'], game['home']['totalPoints'],
        game['away']['teamId'], game['away']['totalPoints']
    ] for game in d['schedule']]
df = pd.DataFrame(df, columns=['Week', 'Team1', 'Score1', 'Team2', 'Score2'])
df['Type'] = ['Regular' if w<=14 else 'Playoff' for w in df['Week']]
df.head()

KeyError的出现是因为没有参数的请求没有'schedule'信息。您可以执行d.keys()来查看dict有哪些键