>>> z = [['var', ['list']], ['x1', ['x','y','z']], ['x2', ['a','b','c']]]
要重新排列它,可能需要:
>>> [ [[x, y] for y in lst] for x, lst in z]
[[['var', 'list']], [['x1', 'x'], ['x1', 'y'], ['x1', 'z']], [['x2', 'a'], ['x2', 'b'], ['x2', 'c']]]
或者,进一步重新安排:
>>> a = []
>>> for x in [ [[x, y] for y in lst] for x, lst in z]:
... a += x
...
>>> a
[['var', 'list'], ['x1', 'x'], ['x1', 'y'], ['x1', 'z'], ['x2', 'a'], ['x2', 'b'], ['x2', 'c']]
data = [['var', 'list'], ['x1', ['x','y','z']], ['x2', ['a','b','c']]]
final = []
for pair in data:
if pair == ['var', 'list'] :
final.append(pair)
else:
for entry in pair[1]:
final.append([pair[0], entry])
print(final)
让我们从我对你的首发名单的解释开始:
要重新排列它,可能需要:
或者,进一步重新安排:
这不是一个最佳的解决方案,但是它使用非常基本的python命令,这样您就可以跟踪正在发生的事情。你知道吗
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