import random
from IPython.display import clear_output
dictionary = open("words_50000.txt","r")
dict_5000 = dictionary.readlines()
guess = random.choice(dict_5000).lower().strip('\n')
no_of_letters = len(guess)
game_str = ['-']*no_of_letters
only_length=[]
def word_guesser():
only_length_words()
print(dict_5000)
def only_length_words():
for i in range(len(dict_5000)):
if len(dict_5000[i].strip('\n'))!=no_of_letters:
dict_5000.pop(i)
word_guesser()
--------------------------------------------------------------------------- IndexError Traceback (most recent call last) in () 20 dict_5000.pop(i) 21 ---> 22 word_guesser()
in word_guesser() 11 12 def word_guesser(): ---> 13 only_length_words() 14 print(dict_5000) 15
in only_length_words() 17 def only_length_words(): 18 for i in range(len(dict_5000)): ---> 19 if len(dict_5000[i].strip('\n'))!=no_of_letters: 20 dict_5000.pop(i) 21
IndexError: list index out of range
问题是您正在使用
pop()
,这会破坏列表,但您也在对列表进行迭代。所以,假设列表中有一个元素,你弹出了。现在,残缺列表的长度比原始列表短,但是for循环仍然会尝试迭代,直到列表的原始长度,这会导致IndexError
。你知道吗相关问题 更多 >
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