我刚开始在Python周围转来转去,虽然我很兴奋,但似乎我离Python思维还很远。
这是一个方法的例子,它的“次优”一词到处都是。 虽然这对于我相对较小的数据集来说已经足够了,但我想知道如何才能更好地编写它?
import pandas as pd
from pandas import DataFrame
# create sample log data frame
lg = pd.DataFrame(['Access violation at address 00A97...',
'Try to edit the splines or change...',
'Access violation at address 00F2B...',
'Please make sure the main electro...'], columns=['lg_msg'])
# define message classification
err_messages = [['Access violation', 'ACC-VIOL', 'PROG'],
['Please make sure th', 'ELE-NOT-PLACED', 'MOD'],
['Try to edit the splines', 'TRY-EDIT-SPLINES', 'MOD']]
# lookup code
def message_code(msg_text):
for msg in err_messages:
if msg_text.startswith(msg[0]):
return msg[1]
return ''
# lookup type
def message_type(msg_text):
for msg in err_messages:
if msg_text.startswith(msg[0]):
return msg[2]
return ''
lg['msg_code'] = lg['lg_msg'].apply(lambda x: message_code(x))
lg['msg_type'] = lg['lg_msg'].apply(lambda x: message_type(x))
我尝试创建一个函数来计算日志条目代码并立即键入:
def message_code_type(msg_text):
for msg in err_messages:
if msg_text.startswith(msg[0]):
return (msg[1], msg[2])
return ('', '')
lg['msg_code'], lg['msg_type'] = lg['lg_msg'].apply(lambda x: message_code_type(x))
但是得到:
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-18-72f97d857539> in <module>()
----> 1 lg['msg_code'], lg['msg_code'] = lg['lg_msg'].apply(lambda x: message_code_type(x))
ValueError: too many values to unpack (expected 2)
有没有办法不遍历数据帧两次?
任何反馈都将不胜感激。
import sys
print(sys.version)
3.5.1 |Anaconda 2.4.0 (64-bit)| (default, Jan 29 2016, 15:01:46) [MSC v.1900 64 bit (AMD64)]
pd.__version__
'0.17.1'
目前没有回答
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