当用docutils
解析重构的文本片段并遍历文档节点树时,大多数节点不会在源文本中提供行号。示例:
import io
from pathlib import Path
import docutils.frontend
import docutils.nodes
import docutils.parsers.rst
text = '''
Fizz
====
Lorem ipsum
Buzz
****
Lorem ``ipsum``
.. code-block:: python
x = 0
.. note::
Dolor sit amet
.. code-block:: python
y = 1
'''
class MyVisitor(docutils.nodes.GenericNodeVisitor):
def default_visit(self, node):
print('node: {:>15}, line: {}'.format(type(node).__name__, node.line))
if __name__ == '__main__':
default_settings = docutils.frontend.OptionParser(components=(docutils.parsers.rst.Parser,)).get_default_values()
document = docutils.utils.new_document('mydocs', default_settings)
parser = docutils.parsers.rst.Parser()
parser.parse(io.StringIO(text).read(), document)
visitor = MyVisitor(document)
document.walk(visitor)
运行此代码将产生:
node: document, line: None
node: section, line: 3
node: title, line: 3
node: Text, line: None
node: paragraph, line: 5
node: Text, line: None
node: section, line: 8
node: title, line: 8
node: Text, line: None
node: paragraph, line: 10
node: Text, line: None
node: literal, line: None
node: Text, line: None
node: literal_block, line: 15
node: inline, line: None
node: Text, line: None
node: Text, line: None
node: inline, line: None
node: Text, line: None
node: Text, line: None
node: inline, line: None
node: Text, line: None
node: note, line: None
node: paragraph, line: 18
node: Text, line: None
node: literal_block, line: None
node: inline, line: None
node: Text, line: None
node: Text, line: None
node: inline, line: None
node: Text, line: None
node: Text, line: None
node: inline, line: None
node: Text, line: None
看起来没有一个嵌套节点记录了行号。是否可以在自定义节点visitor impl中访问此信息?我不希望所有节点(如单独的单词节点)都提供行号,但示例代码段中的note
和嵌套的code-block
都不提供行号。你知道吗
目前没有回答
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