如何验证多个用户满足其输入的要求？

Question

我在为无限多的玩家制作一个游戏。每个玩家将猜5个介于1和25之间的数字。（还有一些其他的要求，你会在代码中看到）我的问题是，我希望第一个用户输入他的猜测，如果他的猜测完全满足了要求，我们返回并遍历下一个玩家猜测的名字列表。问题是我不知道如何打破循环，回到“主”循环，得到下一个球员。感谢您对这个问题的建议！你知道吗

while True:
        try:
            for name in name_list:
                guess = input("{}, Enter 5 numbers between 1 and 25 (Seperate with ','): ".format(name))
                guess = guess.split(",")
                guess = [int(i) for i in guess]

                while True:
                    for i in guess:
                        if len(guess) != 5:
                            print("You need to enter 5 numbers")
                            guess = input("{}, Enter 5 numbers between 1 and 25 (Seperate with ','): ".format(name))
                            guess = guess.split(",")
                            guess = [int(i) for i in guess]

                        elif guess.count(i) > 1:
                            print("There can only be one of each number!")
                            guess = input("{}, Enter 5 numbers between 1 and 25 (Seperate with ','): ".format(name))
                            guess = guess.split(",")
                            guess = [int(i) for i in guess]

                        elif i > 25 or i < 1:
                            print("The numbers need to be between 1 and 25")
                            guess = input("{}, Enter 5 numbers between 1 and 25 (Seperate with ','): ".format(name))
                            guess = guess.split(",")
                            guess = [int(i) for i in guess]
                else:
                    break


            guess_list.append(guess)
            print("Your numbers: " + str(guess) + "\n")


        except ValueError:
            print("You need to enter integers and seperate by (',')")
            continue
´´´

Answer 1

我浏览了你的代码，其中有一些突破性的问题。我已经把他们的一个快速的总结，以及（我认为）你正试图做的正确版本。你知道吗

在循环中检查len(guess)时，应该在检查每个元素之前检查一次长度

对于最初的问题，请看一下input_good变量，该变量在for循环中设置为true，如果有任何错误，则设置为False。。。这个变量会让内部while循环知道在一切正常的情况下会自行中断（因为我们一次只能直接中断一个循环）

这是一个起点，接下来您应该看看如何使用函数来处理重复行为，并尽可能少地使用try/except代码（让catch-anywhere处理错误是一个糟糕的做法）

# list of names so it runs
name_list = ['Matthew', 'Luke', 'Mark', 'John']

while True:
    try:
        for name in name_list:
            guess = input("{}, Enter 5 numbers between 1 and 25 (Seperate with ','): ".format(name))
            guess = guess.split(",")
            guess = [int(i) for i in guess]

            while True:
                # This if is on the whole list, so it shouldn't be inside the enumeration
                if len(guess) != 5:
                    print("You need to enter 5 numbers")
                    guess = input("{}, Enter 5 numbers between 1 and 25 (Seperate with ','): ".format(name))
                    guess = guess.split(",")
                    guess = [int(i) for i in guess]
                    # continue will cause the while loop to run again,
                    # causing this if statemtn to run again with the new guess numbers
                    continue

                for i in guess:
                    # We need to break out of 2 loops now...
                    # So we set a flag that the outer loop will check and break if the input is good
                    input_good = True
                    if guess.count(i) > 1:
                        print("There can only be one of each number!")
                        guess = input("{}, Enter 5 numbers between 1 and 25 (Seperate with ','): ".format(name))
                        guess = guess.split(",")
                        guess = [int(i) for i in guess]
                        input_good = False
                        # input good False means the outer loop won't break,
                        # but we still want to break out of the for loop and back into the while loop
                        break

                    elif i > 25 or i < 1:
                        print("The numbers need to be between 1 and 25")
                        guess = input("{}, Enter 5 numbers between 1 and 25 (Seperate with ','): ".format(name))
                        guess = guess.split(",")
                        guess = [int(i) for i in guess]
                        input_good = False
                        break # as above
                print('run %s' % str(input_good))
                if input_good:
                    break
            # This else break does nothing as it is only hit when the loop condition is false and while True is always true
            #else:
            #    break
        guess_list.append(guess)
        print("Your numbers: " + str(guess) + "\n")


    except ValueError:
        print("You need to enter integers and seperate by (',')")
        continue