在Python中访问JSON上的字典

Question

我试图将JSON中复制的字典的值赋给代码中的变量。你知道吗

这是复制到.json上的字典：

"Monetarios": [{"MIFID_NO_CURR_RISK":"B1"},{"MIFID_CURR_RISK":"B2"}],
          "Monetario Dinamico": [{"MIFID_NO_CURR_RISK":"B1"},{"MIFID_CURR_RISK":"B2"}],
          "Renta Fija Corto Plazo": [{"MIFID_NO_CURR_RISK":"B1"},{"MIFID_CURR_RISK":"B2"}],
          "Garantizados de RF": [{"MIFID_NO_CURR_RISK":"B1"},{"MIFID_CURR_RISK":"B2"}],
          "Renta Fija Largo Plazo": [{"MIFID_NO_CURR_RISK":"B1"},{"MIFID_CURR_RISK":"B2"}]

我试着在屏幕上展示“Renta Fija Corto Plazo”的MIFID NoCurr风险B1

我这样做，效果很好：

carga_dict['Renta Fija Corto Plazo']
Out[56]: [{u'MIFID_NO_CURR_RISK': u'B1'}, {u'MIFID_CURR_RISK': u'B2'}]

但当我这么做的时候，我得到了一个错误：

carga_dict['Renta Fija Corto Plazo']['MIFID_NO_CURR_RISK']
Traceback (most recent call last):

  File "<ipython-input-57-46b56ce8491a>", line 1, in <module>
    carga_dict['Renta Fija Corto Plazo']['MIFID_NO_CURR_RISK']

TypeError: list indices must be integers, not str

Answer 1

carga_dict['Renta Fija Corto Plazo'][0]['MIFID_NO_CURR_RISK']

carga_dict['Renta Fija Corto Plazo']是字典列表。因此，您必须首先选择list元素并找到相应的键。你知道吗