如何将model（）分配给QListVi

Question

下面的代码创建一个QListView。MyClass（从QAbstractListModel继承）的实例被分配给它的self.setModel(self.model)。如果单击视图，我可以选择列表中的项目（因此它们确实存在）。但没有显示项目的名称。如何控制QListView项的显示方式？你知道吗

from PyQt4 import QtCore, QtGui
app=QtGui.QApplication(sys.argv)

class MyClass(QtCore.QAbstractListModel):
    def __init__(self):
        super(MyClass, self).__init__()
        self.elements={'Animals':['Bison','Panther','Elephant'],'Birds':['Duck','Hawk','Pigeon'],'Fish':['Shark','Salmon','Piranha']}
    def rowCount(self, index=QtCore.QModelIndex()):
        return len(self.elements)        
    def data(self, index, role=QtCore.Qt.DisplayRole):
        print'MyClass.data():',index,role

class ListView(QtGui.QListView):
    def __init__(self):
        super(ListView, self).__init__()
        self.model=MyClass()
        self.setModel(self.model)
        self.show()

window=ListView()
sys.exit(app.exec_())

Answer 1

我不知道如何使用字典来查找元素，但是使用列表：

    self.elements=['Bison','Panther','Elephant','Duck','Hawk','Pigeon','Shark','Salmon','Piranha']

只需在data()方法中返回self.elements[index.row()]。例如：

class MyClass(QtCore.QAbstractListModel):
    def __init__(self):
        super(MyClass, self).__init__()
        self.elements=['Bison','Panther','Elephant','Duck','Hawk','Pigeon','Shark','Salmon','Piranha']
    def rowCount(self, index=QtCore.QModelIndex()):
        return len(self.elements)        
    def data(self, index, role=QtCore.Qt.DisplayRole):
        print'MyClass.data():',index,role
        if index.isValid() and role == QtCore.Qt.DisplayRole:
            return QtCore.QVariant(self.elements[index.row()])
        else:
            return QtCore.QVariant()