如何根据另一个数组的信息将数组中的值更改为true和false

Question

我正在使用scikit learn，我有fetch\u olivetti\u faces的faces数据。我有第二组中所有戴眼镜的脸的指数。但是，在第一个数组中，我有所有的脸（无论是否戴眼镜）。现在我想训练模特知道一张脸是否戴着眼镜。你知道吗

我的问题是，我想根据第二个数组中给出的索引，将包含所有面的第一个数组（目标数组）中的值更改为false（不戴眼镜）和true（戴眼镜）。你知道吗

这个问题是一般性的，你不需要了解scikit就可以学会回答它。只是关于操纵数组的知识。你知道吗

在第一个数组中，我有以下元素：

faces.target
array([ 0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  1,  1,  1,  1,  1,  1,  1,
        1,  1,  1,  2,  2,  2,  2,  2,  2,  2,  2,  2,  2,  3,  3,  3,  3,
        3,  3,  3,  3,  3,  3,  4,  4,  4,  4,  4,  4,  4,  4,  4,  4,  5,
        5,  5,  5,  5,  5,  5,  5,  5,  5,  6,  6,  6,  6,  6,  6,  6,  6,
        6,  6,  7,  7,  7,  7,  7,  7,  7,  7,  7,  7,  8,  8,  8,  8,  8,
        8,  8,  8,  8,  8,  9,  9,  9,  9,  9,  9,  9,  9,  9,  9, 10, 10,
       10, 10, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 11, 11, 11, 11,
       11, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 13, 13, 13, 13, 13, 13,
       13, 13, 13, 13, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 15, 15, 15,
       15, 15, 15, 15, 15, 15, 15, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16,
       17, 17, 17, 17, 17, 17, 17, 17, 17, 17, 18, 18, 18, 18, 18, 18, 18,
       18, 18, 18, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 20, 20, 20, 20,
       20, 20, 20, 20, 20, 20, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 22,
       22, 22, 22, 22, 22, 22, 22, 22, 22, 23, 23, 23, 23, 23, 23, 23, 23,
       23, 23, 24, 24, 24, 24, 24, 24, 24, 24, 24, 24, 25, 25, 25, 25, 25,
       25, 25, 25, 25, 25, 26, 26, 26, 26, 26, 26, 26, 26, 26, 26, 27, 27,
       27, 27, 27, 27, 27, 27, 27, 27, 28, 28, 28, 28, 28, 28, 28, 28, 28,
       28, 29, 29, 29, 29, 29, 29, 29, 29, 29, 29, 30, 30, 30, 30, 30, 30,
       30, 30, 30, 30, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 32, 32, 32,
       32, 32, 32, 32, 32, 32, 32, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33,
       34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 35, 35, 35, 35, 35, 35, 35,
       35, 35, 35, 36, 36, 36, 36, 36, 36, 36, 36, 36, 36, 37, 37, 37, 37,
       37, 37, 37, 37, 37, 37, 38, 38, 38, 38, 38, 38, 38, 38, 38, 38, 39,
       39, 39, 39, 39, 39, 39, 39, 39, 39])

在第二个数组中，我有以下元素，其中包含第一个数组中戴眼镜的人的索引：

print(glasses)
[10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 30, 31, 32, 37, 38, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 63, 64, 69, 120, 121, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 137, 138, 139, 160, 161, 164, 165, 166, 167, 168, 169, 180, 181, 182, 185, 189, 190, 191, 192, 194, 196, 197, 198, 199, 260, 261, 262, 263, 264, 265, 266, 267, 268, 269, 270, 271, 272, 273, 274, 275, 276, 277, 278, 279, 300, 301, 302, 303, 304, 305, 306, 307, 308, 309, 330, 331, 332, 333, 334, 335, 336, 337, 338, 339, 358, 359, 360, 361, 362, 363, 364, 365, 366, 367, 368, 369]

现在，例如，如果我将数组2中的第一个元素10作为索引传递给第一个数组，如下所示：

faces.target[10]

它会给我一个戴眼镜的人的形象。其余的也一样，11，12。。。等等。你知道吗

现在，我想将第一个数组中的所有元素都转换为false，除了第二个数组中的索引为true的元素。所以：

faces.target[10] = true
faces.target[11] = true 
...
faces.target[367] = true
and so on

Answer 1

要将其保留在numpy空间中，您可以执行以下操作：

import numpy as np

all_faces=np.zeros(4)
is_face_glassed=np.full((4), False)
glassed_faces=np.array([1,3])
for glassed_face in glassed_faces:
    is_face_glassed[glassed_face]=True

记入How to create a numpy array of all True or all False?。你知道吗

Answer 2

试试这个：

final_list = []

for index, element in enumerate(faces_target):
   final_list.append('True') if index in glasses else final_list.append('False')

Answer 3

您可以使用列表：

glasses_label  = [index in glasses for index,_ in enumerate(face_target)]

如果需要的话，您可以将它转换成numpy数组np.array(glasses_label)