我有两个表,命名为projects和actions,每个项目都包含几个action
class Projet(db.Model):
__tablename__ = 'projets'
id = db.Column(db.Integer, primary_key=True)
nom_projet = db.Column(db.String(100))
description_projet = db.Column(db.String(800))
date_affectation = db.Column(db.DateTime, nullable = False)
statut_projet = db.Column(db.String(100))
admin_id = db.Column(db.Integer, db.ForeignKey('admins.id'))
actions = db.relationship('Action', backref='projet',
lazy='dynamic')
def __repr__(self):
return '<Projet: {}>'.format(self.id)
class Action(db.Model):
__tablename__ = 'actions'
id = db.Column(db.Integer, primary_key=True)
projet_id = db.Column(db.Integer, db.ForeignKey('projets.id'))
description = db.Column(db.String(1000))
statut_action = db.Column(db.String(100))
date_action = db.Column(db.DateTime, nullable = False)
date_execution = db.Column(db.DateTime, nullable = True)
def __repr__(self):
return '<Action: {}>'.format(self.id)
我的问题是,我需要在现有项目的基础上创建一个新操作,如图所示, 我需要点击添加按钮,他必须重定向到与项目名称自动选择我的行动形式,我输入的行动细节。你知道吗
这是我第一个添加操作的代码:
@auth.route('/action/add', methods=['GET', 'POST'])
@login_required
def add_action():
form = ActionForm()
if form.validate_on_submit():
action = Action(
projet = form.projet.data,
description = form.description.data,
statut_action = form.statut_action.data,
date_action = form.date_action.data,
date_execution = form.date_execution.data
)
try:
db.session.add(action)
db.session.commit()
flash('You have successfully added a new action.')
except:
flash('Error: action name already exists.')
return redirect(url_for('auth.list_projets'))
return render_template('admin/actions/action.html', action="Add", form=form,
title="ADD ACTION")
步骤:
/project/1/actions/add
意味着为id为1的项目加载带有新操作表单的页面ActionForm
中删除project
字段,因为它是使用path param处理的product_name
变量试试看
相关问题 更多 >
编程相关推荐