代码必须是一个浮点数，所以如何将其转换为整数

Question

import sys

def setup(core, actor, buff):
    core.skillModService.addSkillMod(actor, 'expertise_damage_all', 10)
    core.skillModService.addSkillMod(actor, 'expertise_action_all', 10)
    core.skillModService.addSkillMod(actor, 'movement_resist_snare', 100)
    core.skillModService.addSkillMod(actor, 'movement', 0.5)
    return

def removeBuff(core, actor, buff):
    core.skillModService.deductSkillMod(actor, 'expertise_damage_all', 10)
    core.skillModService.deductSkillMod(actor, 'expertise_action_all', 10)
    core.skillModService.deductSkillMod(actor, 'movement_resist_snare', 100)
    core.skillModService.deductSkillMod(actor, 'movement', 1)
    return

我得到一个错误：

File "scripts/buffs/of_charge_1.py", line 7, in setup
    core.skillModService.addSkillMod(actor, 'movement', 0.5)
TypeError: addSkillMod(): 3rd arg can't be coerced to int

在主代码Java中，我将它设置为一个float，否则它将不起作用，所以在这里我试图将它设置为一个整数，但我仍然坚持要做什么才能使它成为int

Answer 1

不仅仅是。。。你知道吗

a = 0.5
print int(a)
>>> 0

Answer 2

你可以试着投。你知道吗

core.skillModService.addSkillMod(actor, 'movement', int(0.5))