有没有一种（简单的）方法来解析Python中的CRL？

Question

我正在尝试做一些愚蠢的事情：加载一个CRL并输出已吊销证书序列的列表。

使用M2Crypto加载CRL时使用：

import M2Crypto
crl = M2crypto.X509.load_crl('my.crl')

但我真的很惊讶返回的对象只有一个usefull

crl.as_text()

使用一些regexp，我可以解析输出以检索我的已吊销序列。但还有别的办法吗？

关于信息，这里是一个经典的CRL as_文本输出。

Certificate Revocation List (CRL):
        Version 2 (0x1)
        Signature Algorithm: sha1WithRSAEncryption
        Issuer: /C=FR/ST=IDF/L=Paris/O=XXXXX/OU=XXXXX/CN=XXXXX Certificate Authority
        Last Update: Nov  6 21:49:51 2010 GMT
        Next Update: Nov  7 21:49:51 2010 GMT
Revoked Certificates:
    Serial Number: 02
        Revocation Date: Aug 10 15:40:09 2010 GMT
    Serial Number: 03
        Revocation Date: Sep  9 15:12:24 2010 GMT
    Serial Number: 05
        Revocation Date: Aug 17 14:18:22 2010 GMT
    Serial Number: 06
        Revocation Date: Aug 18 08:57:15 2010 GMT
    Signature Algorithm: sha1WithRSAEncryption
        d1:05:da:1f:c0:1c:68:78:0e:e2:ea:78:de:b8:b2:58:9c:ba:
        b4:7c:c5:e8:2a:8d:8c:82:1d:4b:ed:a7:2d:cb:f6:bf:da:fa:
        38:a4:7a:3d:2b:19:6c:7a:ba:4c:1c:4c:e4:d8:e6:20:3d:0a:
        95:03:75:bf:17:cf:97:ce:3e:4a:93:1c:a6:4c:36:62:97:a2:
        d3:be:f2:78:38:89:13:3e:d4:b0:80:a1:24:52:0d:3a:01:67:
        0d:4f:e7:0b:07:0c:80:04:b7:25:66:a4:61:36:dd:3a:24:29:
        30:67:f6:23:31:34:6f:0b:a8:30:c1:c9:b7:ee:4e:2b:7a:e7:
        6b:31:7d:0b:cb:12:8a:7c:5f:7e:73:a0:42:8d:ea:4f:f7:76:
        ce:1b:0b:6c:6a:3e:eb:08:a6:d6:67:81:cb:cb:98:6d:40:ec:
        8c:e5:a5:f7:f0:ed:0c:7f:38:fd:42:3d:19:c4:69:ec:eb:71:
        7a:e1:30:b4:81:98:f5:00:a0:bd:ac:75:46:15:e6:2b:1c:da:
        f4:09:19:e5:1b:4e:c9:a4:7c:11:79:24:a4:3b:13:84:84:a7:
        5b:0e:07:80:ae:ae:26:8e:d7:b3:cb:b8:6c:79:df:9d:26:b0:
        34:bc:c1:f4:8f:4b:3e:f5:9b:d0:e3:e7:ab:37:27:f6:79:09:
        47:fb:76:07