解码错误值错误：python中以16为基数的int（）的文本无效：'\xe8'

Question

我有一个unicode字符串，因此我想检查字符是连续位还是起始位，以便通过简单的程序将unicode字符的数量计算为

#!/usr/bin/env python
# -*- coding: utf-8 -*-



def arg(str):

  i = 0
  j = 0
  print i

  for test in str:
    print test
    value = int(test,16)
    if (value & 0xc0) != 0x80:
        j=j+1
        print "hello"

  print j
  #return j






def main():
    print "inside main"

    new = "象形字"

    charlen = len(new)
    print charlen
    tes = new.decode('utf-8')

    declen = len(tes)
    print declen


    data = tes.encode('utf-8')


    # print self_len

    enclen = len(data)
    print enclen

    print data

    arg(data)







if __name__ == "__main__":
    main()

运行该代码将错误显示为

象形字[Decode error - output not utf-8]
Traceback (most recent call last):
  File "/Users/laxmi518/Documents/laxmi/code/C/python-c/python_unicode.py", line 69, in <module>
    main()
  File "/Users/laxmi518/Documents/laxmi/code/C/python-c/python_unicode.py", line 52, in main
    arg(data)
  File "/Users/laxmi518/Documents/laxmi/code/C/python-c/python_unicode.py", line 16, in arg
    value = int(test,16)
ValueError: invalid literal for int() with base 16: '\xe8'
[Finished in 0.1s with exit code 1]