我有一个熊猫数据框如下。
df
A B
date_time
2014-07-01 06:03:59.614000 62.1250 NaN
2014-07-01 06:03:59.692000 62.2500 NaN
2014-07-01 06:13:34.524000 62.2500 241.0625
2014-07-01 06:13:34.602000 62.2500 241.5000
2014-07-01 06:15:05.399000 62.2500 241.3750
2014-07-01 06:15:05.399000 62.2500 241.2500
2014-07-01 06:15:42.004000 62.2375 241.2500
2014-07-01 06:15:42.082000 62.2375 241.3750
2014-07-01 06:15:42.082000 62.2375 240.2500
我想把这个频率改成有规律的间隔。但得到以下错误:
new = df.asfreq('1Min')
>>error: cannot reindex from a duplicate axis
现在,我明白为什么会这样。由于我的时间粒度很高(以毫秒为单位),但不规则,所以我每分钟甚至每秒都会得到多个读数。所以我试着把这些毫秒的读数合并成分钟,并去掉下面的重复数据。
# try to convert the index to minutes and drop duplicates
df['index'] = df.index
df['minute_index']= df['index'].apply( lambda x: x.strftime('%Y-%m-%d %H:%M'))
df.drop_duplicates(cols = 'minute_index', inplace = True, take_last = True)
df_by_minute = df.set_index('minute_index')
df_by_minute
A B index
minute_index
2014-07-01 06:03 62.2500 NaN 2014-07-01 06:03:59.692000
2014-07-01 06:13 62.2500 241.50 2014-07-01 06:13:34.602000
2014-07-01 06:15 62.2375 240.25 2014-07-01 06:15:42.082000
# now change the frequency to 1 minute but I just get NaNs (!)
df_by_minute.asfreq('1Min')
A B index
2014-07-01 06:03:00 NaN NaN NaT
2014-07-01 06:04:00 NaN NaN NaT
2014-07-01 06:05:00 NaN NaN NaT
2014-07-01 06:06:00 NaN NaN NaT
2014-07-01 06:07:00 NaN NaN NaT
2014-07-01 06:08:00 NaN NaN NaT
2014-07-01 06:09:00 NaN NaN NaT
2014-07-01 06:10:00 NaN NaN NaT
2014-07-01 06:11:00 NaN NaN NaT
2014-07-01 06:12:00 NaN NaN NaT
2014-07-01 06:13:00 NaN NaN NaT
2014-07-01 06:14:00 NaN NaN NaT
2014-07-01 06:15:00 NaN NaN NaT
正如你所见,它不起作用。。有人能帮忙吗?我要实现的是得到一个函数,该函数返回A or B as of DateTime
,DateTime将以1分钟为增量。
目前没有回答
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