我是雪盲从看例子,不完全符合我的情况。。。或者他们会。因此,如果有很好的例子,我还不能用大约3周的Python经验来解释它们
我有一个脚本,可以查询数据库,收集可下载电影的列表,然后将它们逐个下载到您选择的目录中。我想让它下载4或5一次,因为它需要一个年龄做。你知道吗
这里是一个简化的版本,我尝试做什么,myapp是我的数据库应用程序。不过,它似乎只是按顺序运行,尽管它说它正在启动两个线程
listOfIDs是一些容器的id,这些容器可能有电影,也可能没有电影,然后versionS返回电影文件名。你知道吗
import threading
import myapp_api
listOfIDs = (14809, 14808, 14807, 14806, 14805, 14804, 14803)
for ID in listOfIDs:
versionS = myapp.find_one('Version', [['id', 'is', ID]], ['uploaded_movie'])
ipath = ('/Users/me/Desktop/scripts/downloads/')
exitFlag = 0
class myThread (threading.Thread):
def __init__(self, threadID, name, counter):
threading.Thread.__init__(self)
self.threadID = threadID
self.name = name
self.counter = counter
def run(self):
print "Starting " + self.name
for ID in listOfIDs:
print "\nID= " + str(ID) + "\n"
downLoad(ID)
print "Exiting " + self.name
def downLoad(ID):
versionS = myapp.find_one('Version', [['id', 'is', ID]], ['uploaded_movie'])
path = ipath + (str(versionS).split("'")[5])
result = myapp.download_attachment(attachment=versionS['uploaded_movie'], file_path=path)
print "Thread Name = " + threadName
# Create new threads
thread1 = myThread(1, "Thread-1", 1)
thread2 = myThread(2, "Thread-2", 2)
# Start new Threads
thread1.start()
thread2.start()
print "Exiting Main Thread"
好的,所以我修改了代码来接受建议ShadowRanger
,它仍然只是一次下载一个,我把它塞进什么地方了吗。。。代码现在是这样的。你知道吗
import threading
import myapp_api
from collections import deque
listOfIDs = (14809, 14808, 14807, 14806, 14805, 14804, 14803)
for ID in listOfIDs:
versionS = myapp.find_one('Version', [['id', 'is', ID]], ['uploaded_movie'])
ipath = ('/Users/me/Desktop/scripts/downloads/')
def downLoad(ID):
path = ipath + (str(versionS).split("'")[5])
result = myapp.download_attachment(attachment=versionS['uploaded_movie'], file_path=path)
with closing(multiprocessing.Pool(4)) as pool:
deque(pool.imap_unordered(downLoad, listOfIDs), maxlen=0)
最后,ShadowRanger
给出的所有建议都是正确的,错误在于我做了一些不正确的事情(我想我很早就迭代了listOfIDs,只把最后一个传递给函数)。。。这是最后的工作版本。你知道吗
import threading
import myapp_api
from collections import deque
listOfIDs = (14809, 14808, 14807, 14806, 14805, 14804, 14803)
ipath = ('/Users/me/Desktop/scripts/downloads/')
def downLoad(ID):
versionS = myapp.find_one('Version', [['id', 'is', ID]], ['uploaded_movie'])
path = ipath + (str(versionS).split("'")[5])
result = myapp.download_attachment(attachment=versionS['uploaded_movie'], file_path=path)
with closing(multiprocessing.Pool(4)) as pool:
deque(pool.imap_unordered(downLoad, listOfIDs), maxlen=0)
我看不出线程是如何分裂的。看起来他们下载的东西是一样的。你知道吗
如果目标是基于已知ID下载一堆文件,
multiprocessing
有一个.dummy
模块,它可以像multiprocessing
一样工作,但使用线程来实现,这为您提供了一个简单的线程池:相关问题 更多 >
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