在python中完成函数调用后，如何访问函数的局部变量？

Question

我在网上发现，函数调用完成后，函数的局部变量不能从外部访问，我试图执行这个程序，但它抛出了一个错误，变量没有定义。我的密码是

xyz=list()
n=0
def length(g):
    i=0
    n=g
    v=input("no of")
    while i<v:
        c=input("Enter the 1st dimension:")
        j=input("Enter the 2nd dimension:")
        i=i+1
        xyz.append(c)
        xyz.append(j)
        return c
        return j
        return n
def prod():
    global c
    for i in xyz:
        if n<c and n<j:
            print "Upload another"
        elif n==c and n==j:
            print "Accepted"
        else:
            print "Crop it"
       length(input("ENter the length"))
       prod()
       print xyz

它抛出这样的错误

Traceback (most recent call last): File "C:\Python27\pic.py", line 32, in prod() `File "C:\Python27\pic.py", line 21, in prod if n

Answer 1

我想这就是你想做的

xyz=list()
n=0
def length(g):
    i=0
    n=g
    v=input("no of")
    global xyz
    while i<v:
        c=input("Enter the 1st dimension:")
        j=input("Enter the 2nd dimension:")
        i=i+1
        xyz.append(c)
        xyz.append(j)
        return c,j,n


def prod():
    global xyz
    c,j,n = length(input("ENter the length"))
    for i in xyz:
        if n<c and n<j:
            print "Upload another"
        elif n==c and n==j:
            print "Accepted"
        else:
            print "Crop it"

prod()
print xyz

输出

ENter the length 2
no of 2
Enter the 1st dimension: 1
Enter the 2nd dimension: 2
Crop it
Crop it
[1, 2]