如果输入数字0，如何结束while循环并遵循其他说明

Question

我的代码将所有用户输入的项目放入一个列表中 我希望它在输入0时停止，并遵循其他命令，例如排序列表、删除最高值和最低值，然后找到它们的平均值 以下是迄今为止的代码：

i = 0
sizes = []
while i == 0:
    size = int(input("Enter the weight of your parcel in grams, enter 0 when done: "))
    sizes.append(size)
    if size < 1:
        break
sortedsizes = sorted(sizes)
largest = max(sizes)
smallest = min(sizes)
sizes.remove(largest)
sizes.remove(smallest)
print(sizes)

Answer 1

您不需要i，也不希望包的重量小于0。你可能想考虑用float代替int——在我住的地方，我们测量kg的包裹或g的字母——两者都将包括分数（1.235kg或5.28g）。你知道吗

如果有人输入"22kg"，任何数字转换都会崩溃-您应该注意：

sizes = []
while True:
    try:
        size = int(input("Enter the weight of your parcel in grams, enter 0 when done: "))
        if size > 0:  
            sizes.append(size)
        elif size == 0:
            break
        else:
            raise ValueError()  # negative weight
    except ValueError:
        print("Only positive numbers or 0 to quit. Do not input text or kg/g/mg.")

sortedsizes = sorted(sizes) # you do nothing with this - why sort at all?
largest = max(sizes)
smallest = min(sizes)
sizes.remove(largest)
sizes.remove(smallest)
print(sizes)  # this prints the unsorted list that got min/max removed...

输出：

Enter the weight of your parcel in grams, enter 0 when done: 4 
Enter the weight of your parcel in grams, enter 0 when done: 3 
Enter the weight of your parcel in grams, enter 0 when done: 5 
Enter the weight of your parcel in grams, enter 0 when done: 6 
Enter the weight of your parcel in grams, enter 0 when done: -1 
Only positive numbers or 0 to quit. Do not input text or kg/g/mg.
Enter the weight of your parcel in grams, enter 0 when done: DONE 
Only positive numbers or 0 to quit. Do not input text or kg/g/mg. 
Enter the weight of your parcel in grams, enter 0 when done: 2 
Enter the weight of your parcel in grams, enter 0 when done: 0

[4, 3, 5]  # this is the unsorted list that got min/max removed...

---

如果您只想从排序列表中删除1个最大值和1个最小值，您可以简单地执行以下操作：

sortedsizes = sorted(sizes)  
maxval = sortedsizes.pop()    # remove last one from sortedsizes  (== max)
minval = sortedsizes.pop(0)   # remove first one from sortedsizes (== min)
print(sortedsizes)            # print the sorted values

独行：

• pop() doku
• try: catch: error handling

Answer 2

如果希望代码在输入0时停止（将大小附加到列表中，并在重复过程后继续执行命令），则必须执行相反的操作。你知道吗

while True:
    size = int(input("Enter the weight of your parcel in grams, enter 0 when done: "))
    sizes.append(size)
    if size < 1:
        break

当语句为false时，代码从sortedsizes = sorted(sizes)命令继续。你知道吗